我希望能够根据数组的内容创建文件。以下是我尝试过的:
class make_files (
$servers = ['server-1','server-2','server-3'],
) {
file { $servers :
path => '/tmp',
content => $servers,
}
}..。但当我这么做的时候.
# puppet apply --modulepath=/root/modules -e 'include make_files'..。我得到了这个输出:
Notice: Compiled catalog for host-001 in environment production in 0.13 seconds
Error: Cannot alias File[server-2] to ["/tmp"] at /root/modules/make_files/manifests/init.pp:9; resource ["File", "/tmp"] already declared at /root/modules/make_files/manifests/init.pp:9我希望有三份文件..。
# ls /tmp/server-?
/tmp/server-1 /tmp/server-2 /tmp/server-3
# cat /tmp/server-?
server-1
server-2
server-3如果有人能告诉我如何将文件命名为: server-1.cfg、server-2.cfg和server-3.cfg,那就太酷了。任何帮助都是非常感谢的!
发布于 2015-04-24 07:37:13
首先,您已经在File['/tmp']文件中定义了资源init.pp。这是你遇到问题的主要原因:
错误:别名Fileserver-2不能在/root//tmp/make_files/舱单/init.pp:9处声明为"/tmp“;资源"File","/tmp”已经声明在/root/模块/make_files/舱单/init.pp:9
请检查路径属性的含义。也许这会澄清问题。创建
$files_to_create = ['/path/server-1','/path/server-2','/path/server-3']然后用它:
file { $files_to_create :
content => $servers,
}还请确保文件系统中已经存在/path目录。到目前为止,木偶还不能创建中间目录。
https://stackoverflow.com/questions/29839273
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