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问窗体和PHP结果显示在同一页上
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Stack Overflow用户

提问于 2015-04-16 15:15:04

回答 5查看 35.9K关注 0票数 3

我在一个页面上有一个表单链接到一个PHP文件(action)，现在PHP结果显示在这个PHP文件/页面中。但我希望结果显示在页面和表单上。我已经彻底搜查过了，到处都找不到。也许你们谁能帮上忙？

代码: /citizens.php (主页)

<form method="post" action="/infoct.php">
<input type="text" name="ID" placeholder="ID">
<input name="set" type="submit">
</form>

代码: /infoct.php

<!DOCTYPE html>
<html>
<head>
<!-- <meta http-equiv="refresh" content="0; url=/citizens.php" /> -->
</head>

<body>

<?php {
$ID2 = isset($_POST['ID']) ? $_POST['ID'] : false;
}

$connect = mysql_connect('localhost', 'root', 'passwd'); 
mysql_select_db ('inhabitants'); 
$sql = "SELECT `Name`, `Surname`, `DOB`, `RPS`, `Address` FROM `citizens` WHERE ID = $ID2";
$res = mysql_query($sql);
echo "<P1><b>Citizen Identification number is</b> $ID2 </p1>";
while($row = mysql_fetch_array($res))
{
    echo "<br><p1><b>First Name:  </b></b>", $row['Name'], "</p1>";
    echo "<br><p1><b>Surname:  </b></b></b>", $row['Surname'], "</p1>";
    echo "<br><p1><b>Date of birth:  </b></b></b></b>", $row['DOB'], "</p1>";
    echo "<br><p1><b>Address:  </b></b></b></b></b>", $row['Address'], "</p1>";
    echo "<br><p1><b>Background information:  </b><br>", $row['RPS'], "</p1>";
}
mysql_close ($connect);

?>
</body>
</html>

我的固定代码多亏了马克·B

<form method="post">
<input type="text" name="ID" placeholder="ID">
<input name="set" type="submit">
</form>
<?php

if ($_SERVER['REQUEST_METHOD'] == 'POST') {
$ID = isset($_POST['ID']) ? $_POST['ID'] : false;
    
$connect = mysql_connect('fdb13.biz.nf:3306', '1858208_inhabit', '12345demien12345'); 
mysql_select_db ('1858208_inhabit'); 
$sql = "SELECT `Name`, `Surname`, `DOB`, `RPS`, `Address` FROM `citizens` WHERE ID = $ID";
$res = mysql_query($sql);
if ($ID > 0) {
    echo "<p><b>Citizen Identification number is</b>  </p>";

    while($row = mysql_fetch_array($res))
    echo "<br><p><b>Surname:  </b></b></b>", $row['Surname'], "</p>";
    echo "<br><p><b>First Name:  </b></b>", $row['Name'], "</p>";
    echo "<br><p><b>Date of birth:  </b></b></b></b>", $row['DOB'], "</p>";
    echo "<br><p><b>Address:  </b></b></b></b></b>", $row['Address'], "</p>";
    echo "<br><p><b>Background information:  </b><br>", $row['RPS'], "</p>";

mysql_close ($connect);
}
    else {
      echo "<p>Enter a citizen ID above</p>";
    }
}
?>

DB卡

post

php

html

回答 5

Stack Overflow用户

回答已采纳

发布于 2015-04-16 15:18:15

单页form+submit处理程序非常基本：

<?php

if ($_SERVER['REQUEST_METHOD'] == 'POST') { 
 ... form was submitted, process it ...
 ... display results ...
 ... whatever else ...
}
?>

<html>
<body>
<form method="post"> ... </form>
</body>
</html>

这就是真正的一切。

票数 7

Stack Overflow用户

发布于 2015-04-16 15:19:24

在同一个页面上使用代码( (citizens.php) )

<?php

if (isset($_POST)) { 
Do manipulation
}
?>

否则使用ajax并从表单中删除操作方法。

<form method="post" id="contactForm">
<input type="text" name="ID" placeholder="ID">
<input name="set" type="buttom" id="submitId">
</form>

<script>
$("#submitId").click(function(){
   var Serialized =  $("#contactForm").serialize();
    $.ajax({
       type: "POST",
        url: "infoct.php",
        data: Serialized,
        success: function(data) {
            //var obj = jQuery.parseJSON(data); if the dataType is not specified as json uncomment this
            // do what ever you want with the server response
        },
   error: function(){
        alert('error handing here');
      }
    });
});
</script>

在您的infact.php 中，将回显数据，这样ajax就可以得到数据作为回报。

票数 2

Stack Overflow用户

发布于 2015-04-16 15:24:17

您可以将所有内容都放在infoct.php中，如下所示：

<!DOCTYPE html>
<html>
<head>
<!-- <meta http-equiv="refresh" content="0; url=/infoct.php" /> -->
</head>

<body>
<form method="post" action="/infoct.php">
<input type="text" name="ID" placeholder="ID" value="<?php isset($_POST['ID']) ? $_POST['ID'] : '' ?>">
<input name="set" type="submit">
</form>
<?php 
    if (isset($_POST['ID'])) {
        $ID2 = $_POST['ID']; // DO NOT FORGET ABOUT STRING SANITIZATION
        $connect = mysql_connect('localhost', 'root', 'usbw'); 
        mysql_select_db ('inhabitants'); 
        $sql = "SELECT `Name`, `Surname`, `DOB`, `RPS`, `Address` FROM `citizens` WHERE ID = $ID2";
        $res = mysql_query($sql);
        echo "<P1><b>Citizen Identification number is</b> $ID2 </p1>";
        while($row = mysql_fetch_array($res))
        {
            echo "<br><p1><b>First Name:  </b></b>", $row['Name'], "</p1>";
            echo "<br><p1><b>Surname:  </b></b></b>", $row['Surname'], "</p1>";
            echo "<br><p1><b>Date of birth:  </b></b></b></b>", $row['DOB'], "</p1>";
            echo "<br><p1><b>Address:  </b></b></b></b></b>", $row['Address'], "</p1>";
            echo "<br><p1><b>Background information:  </b><br>", $row['RPS'], "</p1>";
        }
        mysql_close ($connect);
    }
?>
</body>
</html>

不要忘记字符串的消毒！

票数 0

页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持

原文链接：

https://stackoverflow.com/questions/29679022

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