我有一个JSON字符串,我想要使用Gson - {"Id":3,"Title":"Roskilde","Description":"Famous Danske festival","StartingTime":"2016-06-12T00:00:00","Duration":"02:02:00"},这是当我尝试正确处理工期字段时所得到的错误:
不可解析日期:"02:02:00“
沙漠者(我的想法是添加两种可能的日期反序列化格式):
Gson gSon= new GsonBuilder().registerTypeAdapter(Date.class, new DateDeserializer()).create();
private static final String[] DATE_FORMATS = new String[] {
"yyyy-MM-dd'T'HH:mm:ss",
"HH:mm:ss"
};
private class DateDeserializer implements JsonDeserializer<Date> {
@Override
public Date deserialize(JsonElement jsonElement, Type typeOF,
JsonDeserializationContext context) throws JsonParseException {
for (String format : DATE_FORMATS) {
try {
return new SimpleDateFormat(format, Locale.US).parse(jsonElement.getAsString());
} catch (ParseException e) {
}
}
throw new JsonParseException("Unparseable date: \"" + jsonElement.getAsString()
+ "\". Supported formats: " + Arrays.toString(DATE_FORMATS));
}
}我的事件类(正如您可以看到的,“持续时间”不是类型日期--它是类型时间),我应该做什么来让沙漠者将持续时间理解为类型时间,而不是日期?
private int Id;
private String Title;
private String Description;
private Date StartingTime;
private Time Duration;
public Event(int id, String title,String description, String place, Date startingTime, Time duration)
{
this.Id = id;
this.Description = description;
this.Title = title;
this.StartingTime = startingTime;
this.Duration = duration;
}发布于 2015-04-14 15:35:42
为时间反序列化添加另一个类--确保将返回值转换为" Time“。(另见:cast a String to sql time)
private static final String DATE_FORMAT = "yyyy-MM-dd'T'HH:mm:ss";
private static final String TIME_FORMAT = "HH:mm:ss";
private class DateDeserializer implements JsonDeserializer<Date> {
@Override
public Date deserialize(JsonElement jsonElement, Type typeOF,
JsonDeserializationContext context) throws JsonParseException {
try {
return new SimpleDateFormat(DATE_FORMAT, Locale.US).parse(jsonElement.getAsString());
} catch (ParseException e) {
}
throw new JsonParseException("Unparseable date: \"" + jsonElement.getAsString()
+ "\". Supported formats: " + DATE_FORMAT);
}
}
private class TimeDeserializer implements JsonDeserializer<Time> {
@Override
public Time deserialize(JsonElement jsonElement, Type typeOF,
JsonDeserializationContext context) throws JsonParseException {
try {
String s = jsonElement.getAsString();
SimpleDateFormat sdf = new SimpleDateFormat(TIME_FORMAT, Locale.US);
sdf.parse(s);
long ms = sdf.parse(s).getTime();
Time t = new Time(ms);
return t;
} catch (ParseException e) {
}
throw new JsonParseException("Unparseable time: \"" + jsonElement.getAsString()
+ "\". Supported formats: " + TIME_FORMAT);
}
}注册这两类:
GsonBuilder gSonBuilder= new GsonBuilder();
gSonBuilder.registerTypeAdapter(Date.class, new DateDeserializer());
gSonBuilder.registerTypeAdapter(Time.class, new TimeDeserializer());
Gson gSon = gSonBuilder.create();发布于 2015-04-14 14:46:29
您应该为日期和时间注册反序列化器。就像这样:
try{
// Convert JSON-string to a List of Event objects
Type listType = new TypeToken<ArrayList<Event>>(){}.getType();
GsonBuilder gsonBuilder = new GsonBuilder();
gsonBuilder.registerTypeAdapter(Date.class, new JsonDeserializer<Date>() {
@Override
public Date deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) throws JsonParseException {
try{
DateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss", Locale.ENGLISH);
return df.parse(json.getAsString());
}
catch(ParseException ex){
return null;
}
});
gsonBuilder.RegisterTypeAdapter(Time.class, new JsonDeserializer<Time>(){
@Override
public Time deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) throws JsonParseException {
try{
DateFormat df = new SimpleDateFormat("HH:mm:ss", Locale.ENGLISH);
return df.parse(json.getAsString());
}
catch(ParseException ex){}
}
return null;
}
});
Gson eventGson = gsonBuilder.create();
events = dateGson.fromJson(json, listType);
}
catch(JsonParseException ex){
ex.printStackTrace();
}PS:这段代码没有经过测试,因为我没有太多时间。但我觉得你有个大致的想法。您只需要两个JsonDeserializers,一个用于时间,一个用于约会。
https://stackoverflow.com/questions/29630028
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