在MySQL命令行客户端中运行以下查询时,我遇到了一些奇怪的行为:
SELECT favoriteGenre, firstName, lastName
FROM members
ORDER BY favoriteGenre, firstName;我得到以下结果:
favoriteGenre firstName lastName
crime Jane Field
crime John Sparks
horror Marty Pareene
thriller Mary Newton
romance Jo Scrivener
sciFi Nick Blakeley
nonFiction Bill Swan然而,我期待着这些结果:
favoriteGenre firstName lastName
crime Jane Field
crime John Sparks
horror Marty Pareene
nonFiction Bill Swan
romance Jo Scrivener
sciFi Nick Blakeley
thriller Mary Newton请注意,nonFiction位于第7位,而我预计它将是第4位.
这是用于创建表的SQL:
USE mydatabase;
CREATE TABLE members (
id SMALLINT UNSIGNED NOT NULL AUTO_INCREMENT,
username VARCHAR(30) BINARY NOT NULL UNIQUE,
password CHAR(41) NOT NULL,
firstName VARCHAR(30) NOT NULL,
lastName VARCHAR(30) NOT NULL,
joinDate DATE NOT NULL,
gender ENUM( 'm', 'f' ) NOT NULL,
favoriteGenre ENUM( 'crime', 'horror', 'thriller', 'romance', 'sciFi', 'adventure', 'nonFiction' ) NOT NULL,
emailAddress VARCHAR(50) NOT NULL UNIQUE,
otherInterests TEXT NOT NULL,
PRIMARY KEY (id)
);
INSERT INTO members VALUES( 1, 'sparky', password('mypass'), 'John', 'Sparks', '2007-11-13', 'm', 'crime', 'jsparks@example.com', 'Football, fishing and gardening' );
INSERT INTO members VALUES( 2, 'mary', password('mypass'), 'Mary', 'Newton', '2007-02-06', 'f', 'thriller', 'mary@example.com', 'Writing, hunting and travel' );
INSERT INTO members VALUES( 3, 'jojo', password('mypass'), 'Jo', 'Scrivener', '2006-09-03', 'f', 'romance', 'jscrivener@example.com', 'Genealogy, writing, painting' );
INSERT INTO members VALUES( 4, 'marty', password('mypass'), 'Marty', 'Pareene', '2007-01-07', 'm', 'horror', 'marty@example.com', 'Guitar playing, rock music, clubbing' );
INSERT INTO members VALUES( 5, 'nickb', password('mypass'), 'Nick', 'Blakeley', '2007-08-19', 'm', 'sciFi', 'nick@example.com', 'Watching movies, cooking, socializing' );
INSERT INTO members VALUES( 6, 'bigbill', password('mypass'), 'Bill', 'Swan', '2007-06-11', 'm', 'nonFiction', 'billswan@example.com', 'Tennis, judo, music' );
INSERT INTO members VALUES( 7, 'janefield', password('mypass'), 'Jane', 'Field', '2006-03-03', 'f', 'crime', 'janefield@example.com', 'Thai cookery, gardening, traveling' );幕后到底是怎么回事,是怎么做的呢?这种行为是MySQL特有的吗?
发布于 2015-04-14 14:33:54
favoriteGenre是一个enum,而不是我们大多数人期望看到的文本字段。
正如您可以在文档中阅读的那样,enum的排序是根据它们的索引,而不是它们的文本表示。这使您的查询结果正确。
要根据enum的值对其进行排序,您需要使用CAST(col AS CHAR) (感谢McAdam331添加了这一项,也请参阅他的SQLFiddle)。不过,我建议您对数据库进行适当的规范化。
发布于 2015-04-14 14:23:31
它将首先按照第一列对结果进行排序,如果在一种类型中有多个结果,那么在您的情况下,这就是犯罪;它将根据第二列的定义进行排序。
因此,首先它将对favoriteGenre进行排序,然后按名称排序
你的情况--它是enum,所以它改变了整个游戏。它只会对它的索引进行排序。所以你会有这么奇怪的行为。
希望它能解释
https://stackoverflow.com/questions/29629850
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