如果我在's‘中输入一个单词，它就表示索引超出了范围。如果's‘中的最后一个词以辅音开头，它仍然会说索引超出了范围。

Question

def to_pig_latin(s):
    j = 0 # points to first character in word
    i = 0
    new_sentence_1 = '' # variable to store strings being changed
    vowel_position = 0 # show the position of the first vowel
    number_of_words = 0
    number_of_spaces = s.count(" ") 
    number_of_words = number_of_spaces + 1

    space_position = s.find(" ") # find the position of the first space
    sent = s[:space_position] # slice the first word of the sentence
    old_sent = s[len(sent)+1:] # stores the old sentence without the first word of s

    while number_of_spaces >= 0:
        if sent[j] in ["a", "e", "i", "o", "u"]: # checks if first character is a vowel
            new_sentence = sent + "way" # adds 'way' to the first word
            new_sentence_1 = new_sentence_1 + ' ' + new_sentence # adds the words

        else: # if first character is not equal to a vowel
            for i in range(len(sent)):
                # check to see if first character in s is a vowel
                if s[i] == 'a': 
                    break
                if s[i] == 'e':
                    break
                if s[i] == 'i':
                    break
                if s[i] == 'o':
                    break
                if s[i] == 'u':
                    break

            vowel_position = i # takes position of first vowel reached in word
            consonant_sequence = sent[:vowel_position] # stores all the consonants up to the first vowel, but not the first vowel
            sent = sent[vowel_position:] # slices the word from the first vowel to the end
            new_sentence = sent + 'a' + consonant_sequence + 'ay' # adds strings
            new_sentence_1 = new_sentence_1 + ' ' + new_sentence # adds the words

        s = old_sent # takes the value of old_sent
        space_position = s.find(" ") # find the position of the first space

如果's‘中有一个单词，我如何更改下面的部分以便让它检查？还是字符串中的最后一个词以一个或多个辅音开头的单词结尾？

        if space_position == -1:
            space_position = len(s)
            sent = s[:space_position]
            if sent[j] in ["a", "e", "i", "o", "u"]:
                new_sentence = sent + "way"
                new_sentence_1 = new_sentence_1 + ' ' + new_sentence
                break
            else:
                for i in range(len(sent)):
                    if s[i] == 'a':
                        break
                    if s[i] == 'e':
                        break
                    if s[i] == 'i':
                        break
                    if s[i] == 'o':
                        break
                    if s[i] == 'u':
                        break

            vowel_position = i
            consonant_sequence = sent[:vowel_position]
            sent = sent[vowel_position:]
            new_sentence = sent + 'a' + consonant_sequence + 'ay'
            new_sentence_1 = new_sentence_1 + ' ' + new_sentence            


        sent = s[:space_position]
        old_sent = s[len(sent)+1:]
        number_of_spaces = s.count(" ")
        number_of_words = number_of_spaces + 1

    return new_sentence_1[1:]

# test program for english/piglatin translator

import piglatin

choice = input ("(E)nglish or (P)ig Latin?\n")
action = choice[:1]
if action == 'E':
    s = input("Enter an English sentence:\n")
    new_s = piglatin.to_pig_latin(s)
    print("Pig-Latin:")
    print(new_s)
elif action =='P':
    s = input("Enter a Pig Latin sentence:\n")
    new_s = piglatin.to_english(s)
    print("English:")
    print(new_s)

(E)nglish还是(P)ig拉丁语？E输入一个英语句子: apple (最近一次调用)：文件"/Applications/Wing101.app/Contents/Resources/src/debug/tserver/_sandbox.py"，第9行，在文件“/User/azhar/Desktop/Computer Science/Assition4 (Functions & Strings)/piglatin.py”中，第44行，在to_pig_latin中，在"a“、"e”、"i“、"o”、“u”中输入超出范围的字符串索引。

Answer 1

您在所有数字上都有一个for循环，直到sent的长度为止，但是尝试将其索引到s中。

for i in range(len(sent)):
    if s[i] == 'a':
        break

除了引发IndexError之外，如果len(s)