SBT生成文件不识别“程序集”

Question

我有一个在SBT13.7中工作良好的build.sbt文件。但是在13.8中，它给了我一个“表达式中的类型错误”错误。它在这一行的开头抛出错误：

mergeStrategy in assembly <<= (mergeStrategy in assembly) { (old) =>
{ ...

如果我完全删除mergeStrategy块，它将在该行开头给出相同的“表达式中的类型错误”：

jarName in assembly := "theBigServer.jar"

所以我假设它与“组装”有问题。这是否应该在13.8中有不同的处理方式？

这是完整的build.sbt文件：

organization  := "com.myco"
version       := "0.1"
scalaVersion  := "2.11.6"  
scalacOptions := Seq("-unchecked", "-deprecation", "-encoding", "utf8")

resolvers ++= Seq(
  "spray repo" at "http://repo.spray.io/",
  "Scalaz Bintray Repo" at "http://dl.bintray.com/scalaz/releases"     // for scalaz-stream
)
libraryDependencies ++= {
  val akkaV = "2.3.9"
  val sprayV = "1.3.2"
  Seq(
    "io.spray"            %%   "spray-can"     % sprayV,
    "io.spray"            %%   "spray-routing" % sprayV,
    "io.spray"            %%   "spray-testkit" % sprayV,
    "io.argonaut"         %%   "argonaut"      % "6.0.4",     
    "com.typesafe.akka"   %%   "akka-actor"    % akkaV,
    "com.typesafe.akka"   %%   "akka-testkit"  % akkaV,
    "com.github.nscala-time" %% "nscala-time"  % "1.8.0", 


    "commons-codec" % "commons-codec" % "1.10",
    "com.amazonaws" % "aws-java-sdk" % "1.9.25"      
  )
}
seq(Revolver.settings: _*)

// put this in to eliminate deduplicate errors in sbt-assembly when making fat JAR
mergeStrategy in assembly <<= (mergeStrategy in assembly) { (old) =>
    {
        case PathList(ps @ _*) if ps.last endsWith "ArgumentsProcessor.class" => MergeStrategy.first
        case PathList(ps @ _*) if ps.last endsWith "MatchersBinder.class" => MergeStrategy.first
        case "application.conf" => MergeStrategy.concat
        case "unwanted.txt"     => MergeStrategy.discard
        case x => old(x)
    }
}

jarName in assembly := "theBigServer.jar"
mainClass in assembly := Some("servletRunner.Boot")

Answer 1

好的，修复了它-似乎问题来自我安装sbt的方式。我按照Scala-sbt.org的手册 安装说明 (实际上只是指定unix，而且我也假设它也适用于linux )将它安装到linux 17上。这导致了我在上面看到的问题。然后我卸载，并通过apt-get重新安装使用他们的Debian指令，现在sbt工作良好。我没有花更多的时间去修理我的手动安装。也许有办法让它发挥作用。我也不知道。