gitlab CI构建脚本语法错误

Question

我试图在Gitlab CI中运行一个构建脚本，但是它抱怨一个语法错误，我不明白。

这是我在Gitlab中配置的脚本：

# test syntax of all *.php and *.ctp files
for f in $(find . -name "*.php" -or -name "*.ctp")
do 
    php -l $f
done

这是Gitlab提交后的输出：

cd /opt/gitlab-runner/embedded/service/gitlab-runner/tmp/builds/project-1 && git reset --hard && git clean -fdx && git remote set-url origin http://gitlab-ci-token:xxxxxx@git01.peoplefone.com/web/portals.git && git fetch origin
HEAD is now at da5f9b9 test CI 7
From http://git01.peoplefone.com/web/portals
   da5f9b9..559f74b  develop    -> origin/develop
cd /opt/gitlab-runner/embedded/service/gitlab-runner/tmp/builds/project-1 && git reset --hard && git checkout 559f74be65167b67cd7761cb8cbae8bcb528dd40
HEAD is now at da5f9b9 test CI 7
Previous HEAD position was da5f9b9... test CI 7
HEAD is now at 559f74b... test CI 8
# test syntax of all *.php and *.ctp files
for f in $(find . -name "*.php" -or -name "*.ctp")
/tmp/executor20150409-17218-twsoje: line 12: syntax error near unexpected token `echo'

正如你所看到的，我的剧本里没有任何“回声”声明，有人能帮我吗？非常感谢。

Answer 1

在尝试之后，下面的脚本成功了：

# test syntax of all *.php and *.ctp files
for file in $(find . -name *.php -or -name *.ctp); do
    php -l $file;
done

但我还是不明白上面的错误。