如何使用python从一维数组创建具有3个元素的2d数组

Question

signals=([1998  ,1968  ,1937  ,1827  ,2027,2286  ,2484  ,2266  ,2107  ,1690,1808  ,1927  ,1924  ,1959  ,1889,1819  ,1824  ,1979  ,1919  ,1845,1801  ,1799  ,1952  ,1956  ,1969,2044  ,2100  ,2103  ,2110  ,2375,
    2030  ,1744  ,1699  ,1591  ,1770,1950  ,2149  ,2200  ,2294  ,2146,2241  ,2369  ,2251  ,2126  ,2000,1759  ,1947  ,2135  ,2319  ,2352,2476  ,2296  ,2400  ,3126  ,2304,
    2190  ,2121  ,2032  ,2161  ,2289,2137  ,2130  ,2154  ,1831  ,1899,2117  ,2266  ,2176  ,2089  ,1817,2162  ,2267])

Vectors=[[signals[i-1],signals[i+1],signals[i+3]] for i in range(1,len(signals-4))]
print Vectors

TypeError                                 Traceback (most recent call last)
<ipython-input-2-6f5b7430197d> in <module>()
     16     2190  ,2121  ,2032  ,2161  ,2289,2137  ,2130  ,2154  ,1831  ,1899,2117  ,2266  ,2176  ,2089  ,1817,2162  ,2267])
     17 
---> 18 Vectors=[[signals[i-1],signals[i+1],signals[i+3]] for i in range(1,len(signals-4))]
     19 print Vectors
     20 

TypeError: unsupported operand type(s) for -: 'list' and 'int'


Expected Output:[[signals[0],signals[2], signals[4]],[signals[1],signals[3],signals[5]],[signals[2],signals[4],signals[6]]] 

Answer 1

错误在您的range函数中，您需要插入signals，因为您希望从signals列表的长度中减去4：

range(1,len(signals)-4))

Answer 2

您的paren位置不正确：len(signals-4)应该是len(signals) - 4。