我很擅长编写Linux脚本,但可能需要一些建议。我知道这个问题有点模糊,所以如果你能提供任何帮助,我会很感激的!
以下是个人成长的问题,也是因为我正在写一些网络工具来取乐/学习。没有家庭作业(我是大四学生,我的课都不需要这些东西!)
我正在使用t鲨来获取有关数据包捕获的信息。看上去是这样的:
rachel@Ubuntu-1:~/PCAP$ tshark -r LargeTorrent.pcap -q -z io,phs
===================================================================
Protocol Hierarchy Statistics
Filter:
eth frames:4309 bytes:3984321
ip frames:4119 bytes:3969006
icmp frames:1316 bytes:1308988
udp frames:1408 bytes:1350786
data frames:1368 bytes:1346228
dns frames:16 bytes:1176
nbns frames:14 bytes:1300
http frames:8 bytes:1596
nbdgm frames:2 bytes:486
smb frames:2 bytes:486
mailslot frames:2 bytes:486
browser frames:2 bytes:486
tcp frames:1395 bytes:1309232
data frames:1300 bytes:1294800
http frames:6 bytes:3763
data-text-lines frames:2 bytes:324
xml frames:2 bytes:3205
tcp.segments frames:1 bytes:787
nbss frames:34 bytes:5863
smb frames:17 bytes:3047
pipe frames:4 bytes:686
lanman frames:4 bytes:686
smb2 frames:13 bytes:2444
bittorrent frames:10 bytes:1709
tcp.segments frames:2 bytes:433
bittorrent frames:2 bytes:433
bittorrent frames:1 bytes:258
bittorrent frames:2 bytes:221
bittorrent frames:2 bytes:221
arp frames:146 bytes:8760
ipv6 frames:44 bytes:6555
udp frames:40 bytes:6211
dns frames:18 bytes:1711
dhcpv6 frames:14 bytes:2114
http frames:6 bytes:1014
data frames:2 bytes:1372
icmpv6 frames:4 bytes:344
===================================================================我想让它看起来像:
rachel@Ubuntu-1:~/PCAP$ tshark -r LargeTorrent.pcap -q -z io,phs
===================================================================
Protocol Hierarchy Statistics
Filter:
Protocol Bytes
=====================================
eth 984321
ip 3969006
icmp 1308988
udp 1350786
data 1346228
dns 1176
nbns 1300
http 1596
nbdgm 486
smb 486
mailslot 486
browser 486
tcp 1309232
data 1294800
http 3763
data-text-lines 324
xml 3205
tcp.segments 787
nbss 5863
smb 3047
pipe 686
lanman 686
smb2 2444
bittorrent 1709
tcp.segments 433
bittorrent 433
bittorrent 258
bittorrent 221
bittorrent 221
arp 8760
ipv6 6555
udp 6211
dns 1711
dhcpv6 2114
http 1014
data 1372
icmpv6 344
===================================================================编辑:我将添加原来的问题,目的是了解(伟大的)答案是提供的。
最初,我只想打印“叶”的统计数据,因为eth、ip等都是父母,他们的统计数据对我来说是不必要的。此外,我不想有一个可怕的文本块,只有空格来显示层次结构,我想为父母删除所有的统计数据,并将它们显示为孩子身后的面包屑。
示例:
eth frames:4309 bytes:3984321
ip frames:4119 bytes:3969006
icmp frames:1316 bytes:1308988
udp frames:1408 bytes:1350786
data frames:1368 bytes:1346228
dns frames:16 bytes:1176应该变成
eth:ip:icmp - 1308988 bytes
eth:ip:udp:data - 1346228 bytes
eth:ip:udp:dns - 1176 bytes以保留层次结构并避免打印无用的统计信息。
不管怎么说,埃坦批准的答案完美地解决了这个问题!对于那些在我这个层次上不知道在这个答案之后该如何进行的人,这将帮助你们完成:
filename.awk文件filename.txt文件awk -f filename.awk filename.txtawk -f filename.awk filename.txt >> output.txt )发布于 2015-03-30 01:50:50
我最初认为您想要的输出可以通过这个awk脚本来实现。(我认为这样做可能会更干净,但这似乎足够有效。)
function entry() {
# Don't want to print empty entries.
if (ind[0]) {
printf "%s", ind[0]
for (i = 1; i <= ls; i++) {
printf ":%s", ind[i]
}
split(b, a, /:/)
printf " - %s %s\n", a[2], a[1]
}
}
# Found our data marker. Note that and print the current line.
$1 == "Filter:" {d=1; print; next}
# Print lines until we see our data marker.
!d {print; next}
# Print empty lines.
!NF {print; next}
# Save our trailing line for later.
/===/ {suf=$0; next}
{
# Save our previous indentation level.
ls = s
# Find our new indentation level (by where the first field starts).
s = (match($0, /[^[:space:]]/)-1) / 2
# If the current line is at or below the last indent level print the last line.
if (s <= ls) {
entry()
}
# Save the current line's byte count.
b=$NF
# Save the current line's field name.
ind[s] = $1
}
END {
# Print a final line if we had one.
entry()
# Print the suffix line if we have one.
if (suf) {
print suf
}
}在样本输入上,得到这个输出。
===================================================================
Protocol Hierarchy Statistics
Filter:
eth:ip:icmp - 1308988 bytes
eth:ip:udp:data - 1346228 bytes
eth:ip:udp:dns - 1176 bytes
eth:ip:udp:nbns - 1300 bytes
eth:ip:udp:http - 1596 bytes
eth:ip:udp:nbdgm:smb:mailslot:browser - 486 bytes
eth:ip:tcp:data - 1294800 bytes
eth:ip:tcp:http:data-text-lines - 324 bytes
eth:ip:tcp:http:xml:tcp.segments - 787 bytes
eth:ip:tcp:nbss:smb:pipe:lanman - 686 bytes
eth:ip:tcp:nbss:smb2 - 2444 bytes
eth:ip:tcp:bittorrent:tcp.segments:bittorrent:bittorrent - 258 bytes
eth:ip:tcp:bittorrent:bittorrent:bittorrent - 221 bytes
eth:arp - 8760 bytes
eth:ipv6:udp:dns - 1711 bytes
eth:ipv6:udp:dhcpv6 - 2114 bytes
eth:ipv6:udp:http - 1014 bytes
eth:ipv6:udp:data - 1372 bytes
eth:ipv6:icmpv6:data - 344 bytes
===================================================================但是,您所编辑的输出(如您希望的输出)可能更容易使用sed来处理。
/Filter:/a \
Protocol Bytes \
=====================================
s/frames:[^ ]*//
s/ b/b/
s/bytes:\([^ ]*\)/\1/以输出结束。
===================================================================
Protocol Hierarchy Statistics
Filter:
Protocol Bytes
=====================================
eth 3984321
ip 3969006
icmp 1308988
udp 1350786
data 1346228
dns 1176
nbns 1300
http 1596
nbdgm 486
smb 486
mailslot 486
browser 486
tcp 1309232
data 1294800
http 3763
data-text-lines 324
xml 3205
tcp.segments 787
nbss 5863
smb 3047
pipe 686
lanman 686
smb2 2444
bittorrent 1709
tcp.segments 433
bittorrent 433
bittorrent 258
bittorrent 221
bittorrent 221
arp 8760
ipv6 6555
udp 6211
dns 1711
dhcpv6 2114
http 1014
data 1372
icmpv6 344
===================================================================发布于 2015-03-30 03:47:29
一个带有sed的简单脚本也可以工作。
$ printf "\n==========================================================\n"; printf "Protocol Hierarchy Statistics\nFilter:\n\n";printf "\nProtocol\t\t\t\t Bytes\n================================================\n" && sed -e 's/\(frames[:].*bytes[:]\)\(.*$\)/\2/' dat/tshark.txt | tail -n+4 | head -n-1 && printf "================================================\n"细分为脚本形式(其中dat/tshark.txt是保存tshark输出的文件名):
printf "\n==========================================================\n"
printf "Protocol Hierarchy Statistics\nFilter:\n\n"
printf "\nProtocol\t\t\t\t Bytes\n================================================\n"
sed -e 's/\(frames[:].*bytes[:]\)\(.*$\)/\2/' dat/tshark.txt | tail -n+4 | head -n-1
printf "================================================\n"输出
==========================================================
Protocol Hierarchy Statistics
Filter:
Protocol Bytes
================================================
eth 3984321
ip 3969006
icmp 1308988
udp 1350786
data 1346228
dns 1176
nbns 1300
http 1596
nbdgm 486
smb 486
mailslot 486
browser 486
tcp 1309232
data 1294800
http 3763
data-text-lines 324
xml 3205
tcp.segments 787
nbss 5863
smb 3047
pipe 686
lanman 686
smb2 2444
bittorrent 1709
tcp.segments 433
bittorrent 433
bittorrent 258
bittorrent 221
bittorrent 221
arp 8760
ipv6 6555
udp 6211
dns 1711
dhcpv6 2114
http 1014
data 1372
icmpv6 344
================================================格式化
根据您关于如何根据bytes的可变长度对齐protocol tags信息的注释,您可以使用printf对输出进行格式化。就像伊森一样,我开始研究你最初的问题,把标签整合在一起。我最初的方法是将不同级别读取到不同的关联数组中,这些可以组合到您最初指定的内容中。为此,我必须使用printf生成排成一行的输出。下面是我第一次尝试使用tshark数据的前4层:
declare -i ln=0
declare -A l1 l2 l3 l4
## read each line in file and assing to associative arrays for each level
while read -r line; do
ln=${#line} # base level on length of line read
[ $ln -gt 66 ] && continue;
[ $ln -eq 66 ] && { iface="${line%% *}"; l1[${iface}]="${line##* }"; }
[ $ln -eq 64 ] && { proto="${iface}:${line%% *}"; l2[${proto}]="${line##* }"; }
[ $ln -eq 62 ] && { ptype="${proto}:${line%% *}"; l3[${ptype}]="${line##* }"; }
[ $ln -le 60 ] && { data="${ptype}:${line%% *}"; l4[${data}]="${line##* }"; }
done < "$1"
## output a summary of the file
printf "\n4-level deep summary of file '%s':\n\n" "$1"
for i in "${!l1[@]}"; do
for j in "${!l2[@]}"; do
printf " %-32s %s\n" "$j" "${l2[$j]}"
for k in "${!l3[@]}"; do
printf " %-32s %s\n" "$k" "${l3[$k]}"
for l in "${!l4[@]}"; do
[ "${l%:*}" == "$k" ] && printf " %-32s %s\n" "$l" "${l4[$l]}"
done
done
done
done例如,它产生的产出如下:
eth:ip frames:4119 bytes:3969006
eth:ip:udp frames:1408 bytes:1350786
eth:ip:udp:data frames:1368 bytes:1346228
eth:ip:udp:nbdgm frames:2 bytes:486
eth:ip:udp:nbns frames:14 bytes:1300您可以查看上面代码中的各种printf语句,并查看如何处理对齐。如果你还有其他问题,请告诉我。
https://stackoverflow.com/questions/29336829
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