我试图做一个android登录活动,我创建了一个简单的数据库,其中包含一个表来测试我的登录活动。我的问题是,当我设置一个正确的用户名和密码时,它告诉我用户名和密码是错误的,我在论坛上搜索过,如果有人和我有相似的问题,但我找不到。我真的被困在这个问题上一个多月了。如果有人能帮我扔这个,我会非常感激的。
这是我的Login.java类
public class Login extends Activity implements OnClickListener {
private EditText _myLogin;
private EditText _myPassword;
private String _myContenuLogin;
private String _myContenuPassword;
private boolean _myCheck;
private ProgressDialog _myDialog;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_login);
Button lBtnValidate = (Button) findViewById(R.id.authen_btn_valider);
lBtnValidate.setOnClickListener(this);
Button lBtnCancel = (Button) findViewById(R.id.authen_btn_annuler);
lBtnCancel.setOnClickListener(this);
_myLogin = (EditText) findViewById(R.id.authen_editlogin);
_myPassword = (EditText) findViewById(R.id.authen_editlmdp);
}
@Override
public void onClick(View v) {
if (v.getId() == R.id.authen_btn_valider) {
_myContenuLogin = _myLogin.getText().toString();
_myContenuPassword = _myPassword.getText().toString();
MyAsyncTask myTask = new MyAsyncTask();
myTask.execute(Stat.URL_CHECK);
if (_myCheck) {
Toast.makeText(this, "Bienvenue " + _myContenuLogin,
Toast.LENGTH_SHORT).show();
Intent lIntentHome = new Intent(this, Home.class);
startActivity(lIntentHome);
this.finish();
} else {
Toast.makeText(this,
"Nom d'utilisateur ou mot de passe incorrecte",
Toast.LENGTH_LONG).show();
}
} else if(v.getId() == R.id.authen_btn_annuler){
this.finish();
}
}
private class MyAsyncTask extends AsyncTask<String, Void, Boolean>{
@Override
protected void onPreExecute() {
_myDialog = ProgressDialog.show(Login.this, "Vérification", "Attendez SVP...");
}
@Override
//String...params : Array of Strings , on a mis params[0] puisqu'on a une seule chaîne
protected Boolean doInBackground(String... params) {
ClientHTTP lClientHTTP=new ClientHTTP(Login.this);
ArrayList<NameValuePair> list=new ArrayList<NameValuePair>();
BasicNameValuePair lParamName=new BasicNameValuePair("PARAM_NAME", _myContenuLogin);
list.add(lParamName);
BasicNameValuePair lParamPassword=new BasicNameValuePair("PARAM_PASSWORD", _myContenuPassword);
list.add(lParamPassword);
_myCheck=lClientHTTP.SendToUrl(params[0], list);
return _myCheck;
}
@Override
protected void onPostExecute(Boolean result) {
_myDialog.dismiss();
}
}
}--这是我的Stat.java类,包含有用的字符串
public class Stat {
public static final String DB_NAME = "leoni.db";
public static final String TABLE_NAME = "agent_sos";
public static final String COL_ID = "id";
public static final String COL_NOM_PRENOM = "nom_prenom";
public static final String COL_MDP = "mot_de_passe";
public static final String URL_CHECK = "http://127.0.0.1/check.php";
}这是我的ClientHTTP.java类,它包含连接、获取和发送到url的方法。
public class ClientHTTP {
private Context _mContext;
public ClientHTTP(Context pContext){
_mContext=pContext;
}
//méthode pour lire le contenu d'un URL
public String readFromUrl(String strURL) {
URL clientURL = null;
HttpURLConnection client = null;
// Créer un buffer , StringBuilder() permet de créer une chaîne de caractères modifiable
StringBuilder builder = new StringBuilder();
// Créer un client Http
try {
clientURL = new URL(strURL);
client = (HttpURLConnection) clientURL.openConnection();
} catch (MalformedURLException e1) {
e1.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
// Créer un obejet httpget pour utiliser la methode get
HttpGet httpGet = new HttpGet(strURL);
try {
// récuperer la réponse
HttpResponse response = ((HttpClient) client).execute(httpGet);
//
StatusLine statusLine = response.getStatusLine();
// récuperer le ack
int statusCode = statusLine.getStatusCode();
// si ack =200 connexion avec succée
if (statusCode == 200) {
//récuperer l'entité
HttpEntity entity = response.getEntity();
//récuperer le contenu de l'entité ,
InputStream content = entity.getContent();
BufferedReader reader = new BufferedReader(new InputStreamReader(content));
String line;
while ((line = reader.readLine()) != null) {
builder.append(line);
}
} else {
// errur du chargement
Toast.makeText(_mContext, "pas de connexion", Toast.LENGTH_LONG).show();
}
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return builder.toString();
}
public boolean SendToUrl(String strURL,ArrayList<NameValuePair> nameValuePairs) {
// Créer un buffer
StringBuilder builder = new StringBuilder();
// Créer un client Http
HttpClient client = new DefaultHttpClient();
// Créer un obejet httppost pour utiliser la methode post
HttpPost httppost = new HttpPost(strURL);
try {
//UrlEncodedFormEntit() : An entity composed of a list of url-encoded pairs
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
// récuperer la réponse
HttpResponse response = client.execute(httppost);
StatusLine statusLine = response.getStatusLine();
// récuperer le ack
int statusCode = statusLine.getStatusCode();
// si ack =200 connexion avec succée
if (statusCode == 200) {
HttpEntity entity = response.getEntity();
InputStream content = entity.getContent();
BufferedReader reader = new BufferedReader(
new InputStreamReader(content));
String line;
while ((line = reader.readLine()) != null) {
builder.append(line);
}
} else {
// erreur du chargement
Toast.makeText(_mContext, "pas de connexion", Toast.LENGTH_LONG).show();
}
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return Boolean.parseBoolean(builder.toString());
}
},最后这是我的check.php文件
<?php
/*mysql_real_escape_string Protège une commande SQL de la présence des caractères spéciaux */
$username = mysql_real_escape_string($_REQUEST['PARAM_NAME']);
$password = mysql_real_escape_string($_REQUEST['PARAM_PASSWORD']);
mysql_connect("localhost","root","");
mysql_select_db("leoni");
$result=mysql_query("SELECT nom_prenom,mot_de_passe FROM agent_sos WHERE nom_prenom ='$username' AND mot_de_passe='$password'");
if (mysql_num_rows($result) == 0) {
echo "false";
} else {
echo "true";
}
?>发布于 2015-03-27 00:42:18
我的问题是,我使用的是带有wampsever 2.5的mysql旧版本,所以这是一个兼容性问题,我用以下方式修改了我的php脚本:
<?php
$mysqli = new mysqli("localhost", "root", "", "leoni");
/* Vérification de la connexion */
if (mysqli_connect_errno()) {
printf("Échec de la connexion : %s\n", mysqli_connect_error());
exit();
}
/* Recuperer les params passées */
$username = $mysqli->real_escape_string($_POST['PARAM_NAME']);
$password = $mysqli->real_escape_string($_POST['PARAM_PASSWORD']);
$result = $mysqli->query("SELECT COUNT(*) FROM agent_sos WHERE nom_prenom ='$username' AND mot_de_passe='$password'");
$row = $result->fetch_row();
if($row[0] !=0) {
printf("true");
}else
printf("false");
/* Fermeture de la connexion */
$mysqli->close();
?>我用以下内容更改了URL_CHECK:192.168.1.4,这是命令ipconfig的结果--我的新问题是,它在模拟器上运行得很完美,但是它不能在设备上工作!那是为什么?
发布于 2015-03-20 17:01:50
改变这一点:
public class Stat {
public static final String DB_NAME = "leoni.db";
public static final String TABLE_NAME = "agent_sos";
public static final String COL_ID = "id";
public static final String COL_NOM_PRENOM = "nom_prenom";
public static final String COL_MDP = "mot_de_passe";
public static final String URL_CHECK = "http://127.0.0.1/check.php";
}在这方面:
public class Stat {
public static final String DB_NAME = "leoni.db";
public static final String TABLE_NAME = "agent_sos";
public static final String COL_ID = "id";
public static final String COL_NOM_PRENOM = "nom_prenom";
public static final String COL_MDP = "mot_de_passe";
public static final String URL_CHECK = "http://10.0.2.2/check.php"; //If you are using Emulator or your Computer Ip address by using cmd > ipconfig
}https://stackoverflow.com/questions/29171478
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