NetworkX:绘图图

Question

我试图用Python中的NetworkX绘制一个图形。我使用以下代码：

G=nx.to_networkx_graph(adj)
pos=nx.spring_layout(G)

#G=nx.path_graph(8)
nx.draw(G,pos,labels)
plt.savefig("simple_path.png") # save as png
plt.show() # display

我得到了这个输出：

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但是，我想获得以下带有标签的输出：

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我能对密码做些什么？谢谢。

Answer 1

因此，对于定位，您已经设置了基于pos的spring_layout。pos给出节点的位置。检查它-一旦您定义了它，要求python为您打印pos，看看它在做什么。

下面是另一种代码：

import networkx as nx
import pylab as py
blue_edges = [('B', 'C'), ('B', 'D'), ('B', 'E'), ('E', 'F')]
red_edges = [('A', 'B'), ('A', 'C'), ('C', 'E'), ('D', 'E'), ('D', 'F')]

G=nx.Graph() #define G
G.add_edges_from(blue_edges)
G.add_edges_from(red_edges)

pos = {'A':(0,0), 'B':(1,1), 'C':(1,-1), 'D':(2,1), 'E':(2,-1), 'F':(3,0)}

nx.draw_networkx(G, pos=pos, edgelist = [], node_color = 'k')
nx.draw_networkx(G, pos=pos, nodelist = [], edgelist = blue_edges, edge_color = 'b')
nx.draw_networkx(G, pos=pos, nodelist = [], edgelist = red_edges, edge_color = 'r')

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如果不显示x和y轴，请将最后一点更改为：

nx.draw(G, pos=pos, edgelist = [], node_color = 'k')
nx.draw(G, pos=pos, nodelist = [], edgelist = blue_edges, edge_color = 'b')
nx.draw(G, pos=pos, nodelist = [], edgelist = red_edges, edge_color = 'r')

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