我正在使用ginput的图形选择几个点沿时间信号。有时,当信号太密集时,在选择点之前放大一个区域可能是有用的。我的问题是,zoom to rectangle选项似乎在ginput中得到了考虑。
例如,使用此示例代码:
from __future__ import print_function
from pylab import arange, plot, sin, ginput, show
import numpy as np
t = np.linspace(0,25,500)
plot(t, sin(t))
x = ginput(3)
print("clicked",x)
show()如果我放大了信号的一部分,为缩放区域选择所做的点击将在ginput.有没有办法避免这种情况,并使缩放区域的选择独立于ginput?
发布于 2015-03-20 14:08:29
由于我没有得到任何答案,而且我在这个主题上找不到什么,下面是我如何解决这个问题的方法:我添加了一个预过程,允许用户放大所选区域。当该区域适合采摘点时,用户只需按下"Enter“就可以继续使用ginput。
from __future__ import print_function
from pylab import arange, plot, sin, ginput, show
import matplotlib as plt
from pylab import *
import numpy as np
def closest_point(vec,val):
ind = np.where(vec==min(vec,key=lambda x:abs(x-val)))
return ind[0][0]
t = np.linspace(0,250,5000)
y = sin(t)
fig = plt.figure()
plt.suptitle('chosing points over a possibly dense signal...',fontsize=14)
zoom_ok = False
while not zoom_ok:
plt.plot(t,y)
plt.title('1 - click on the two corners of the area to enlarge',fontsize=12)
zoom = ginput(2,timeout=-1)
xzoom = np.zeros([0])
for i in range(2):
xzoom = np.concatenate((xzoom,[int(closest_point(t,zoom[i][0]))]))
temps_zoom = t[xzoom[0]:xzoom[1]]
dep_zoom = y[xzoom[0]:xzoom[1]]
plt.clf()
plt.plot(temps_zoom,dep_zoom,'b')
plt.title('2 - if zoom ok -> press Enter, otherwise -> mouse click',fontsize=12)
zoom_ok = plt.waitforbuttonpress()
plt.title('3 - you may now select the points ',fontsize=16)
x = ginput(2,timeout=-1)
plt.show() 发布于 2017-11-04 22:32:52
我有同样的问题,我的解决办法是编写一个函数,用鼠标轮缩放,这样我就可以不用点击就可以缩放。我从这个页面上得到了这个函数:
Matplotlib plot zooming with scroll wheel
并修改了函数,使其不超过原来的x和y限制:
def zoom_factory(ax, max_xlim, max_ylim, base_scale = 2.):
def zoom_fun(event):
# get the current x and y limits
cur_xlim = ax.get_xlim()
cur_ylim = ax.get_ylim()
xdata = event.xdata # get event x location
ydata = event.ydata # get event y location
if event.button == 'up':
# deal with zoom in
scale_factor = 1/base_scale
x_scale = scale_factor / 2
elif event.button == 'down':
# deal with zoom out
scale_factor = base_scale
x_scale = scale_factor * 2
else:
# deal with something that should never happen
scale_factor = 1
print(event.button)
# set new limits
new_width = (cur_xlim[1] - cur_xlim[0]) * x_scale
new_height = (cur_ylim[1] - cur_ylim[0]) * scale_factor
relx = (cur_xlim[1] - xdata) / (cur_xlim[1] - cur_xlim[0])
rely = (cur_ylim[1] - ydata) / (cur_ylim[1] - cur_ylim[0])
if xdata - new_width * (1 - relx) > max_xlim[0]:
x_min = xdata - new_width * (1 - relx)
else:
x_min = max_xlim[0]
if xdata + new_width * (relx) < max_xlim[1]:
x_max = xdata + new_width * (relx)
else:
x_max = max_xlim[1]
if ydata - new_height * (1 - rely) > max_ylim[0]:
y_min = ydata - new_height * (1 - rely)
else:
y_min = max_ylim[0]
if ydata + new_height * (rely) < max_ylim[1]:
y_max = ydata + new_height * (rely)
else:
y_max = max_ylim[1]
ax.set_xlim([x_min, x_max])
ax.set_ylim([y_min, y_max])
ax.figure.canvas.draw()
fig = ax.get_figure() # get the figure of interest
# attach the call back
fig.canvas.mpl_connect('scroll_event',zoom_fun)
#return the function
return zoom_fun因此,对于给定的数字:
t = np.linspace(0,250,5000)
y = sin(t)
fig = figure()
ax = fig.add_subplot(111)
plt.plot(t,y)
max_xlim = ax.get_xlim() # get current x_limits to set max zoom out
max_ylim = ax.get_ylim() # get current y_limits to set max zoom out
f = zoom_factory(ax, max_xlim, max_ylim, base_scale=1.1)
show()
x = ginput(3)发布于 2021-05-18 20:41:19
我使用的解决方法是将鼠标按钮参数设置为None
plt.ginput(n=0, timeout=0, mouse_add=None, mouse_pop=None, mouse_stop=None)然后,我使用键盘添加/弹出/停止。(若要添加点,请移动鼠标以纠正位置,并按Spacebar或j等。使用Delete移除最后一点,使用Enter停止。)这样,当我使用矩形缩放与我的鼠标,我没有多余的点。
当然,您可能尝试的一些键盘键可能有其他与窗口/缩放相关的副作用。(例如,Backspace会弹出并重置缩放),所以您必须小心。
https://stackoverflow.com/questions/29145821
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