我使用的是PDO,我找不到哪里出了问题,即使PDO的setAttribute设置为,我也无法得到错误。
$fields = $data['fields'];
$cartID = $data['cartID'];
$sql = "UPDATE ShoppingCart
SET shipToSameLocation_shippingLocationID = :shippingLocationID, shipToSameLocation_shippingMethod = :shippingMethod, shipToSameLocation = 1
WHERE cartID = :cartID";
$query = $conn->prepare($sql);
$query->bindValue(':shippingLocationID', $fields['shipToSameLocation_shippingLocationID'], PDO::PARAM_INT);
$query->bindValue(':shippingMethod', $fields['shipToSameLocation_shippingMethod'], PDO::PARAM_STR);
$query->bindValue(':cartID', $cartID, PDO::PARAM_INT);
$query->execute();里面有什么与PDO有关的问题吗?
发布于 2015-03-18 04:35:45
因为你是明确地说这个值将是一个int,而不是强迫post值进入和int;
$fields = $data['fields'];
$cartID = (int) $data['cartID'];
$sql = "UPDATE ShoppingCart
SET shipToSameLocation_shippingLocationID = :shippingLocationID, shipToSameLocation_shippingMethod = :shippingMethod, shipToSameLocation = 1
WHERE cartID = :cartID";
$query = $conn->prepare($sql);
$query->bindValue(':shippingLocationID', $fields['shipToSameLocation_shippingLocationID'], PDO::PARAM_INT);
$query->bindValue(':shippingMethod', $fields['shipToSameLocation_shippingMethod'], PDO::PARAM_STR);
$query->bindValue(':cartID', $cartID, PDO::PARAM_INT);
$query->execute();您要绑定的其他值也是如此,因此将它们转换为正确的类型,或者更好的是不要使用绑定值。就我个人而言,我从未费心去绑定参数或值,我只是将一个关联数组传递到PDO中。
$locId = (int) $fields['shipToSameLocation_shippingLocationID'];
$method = $fields['shipToSameLocation_shippingMethod'];
$cartId = (int) $data['cartID'];
$params = array(
':shippingLocationID' => $locId ,
':shippingMethod' => $method,
':cartID' => $cartId
);
$query->execute($params);每次都很有魅力。在我工作的大多数地方,其他人最终都采用了这种方法,因为编码和使用的麻烦要小得多,但这取决于您。
https://stackoverflow.com/questions/29114109
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