Python文本文档翻译比较

Question

很简单的问题。我试图创建一个“翻译比较”程序，它读取和比较两个文档，然后返回其他文档中没有的每个单词。这是一个初学者的课程，所以我试图避免使用模糊的内部方法，即使这意味着效率较低的代码。这就是我目前所拥有的..。

def translation_comparison():
   import re
   file1 = open("Desktop/file1.txt","r")
   file2 = open("Desktop/file2.txt","r")
   text1 = file1.read()
   text2 = file2.read()
   text1 = re.findall(r'\w+',text1)
   text2 = re.findall(r'\w+',text2)
   for item in text2:
       if item not in text1:
           return item  

Answer 1

你可以试试像这样的东西

#######Test data
#file1.txt = this is a test
#file2.txt = this a test
#results#
#is

def translation_comparison():
    with open("file1.txt", 'r') as f1:
        f1 = f1.read().split()
    with open("file2.txt", 'r') as f2:
        f2 = f2.read().split()

    for word in f1:
        if word not in f2:
            print(word)


translation_comparison()

此外，使用它也是很好的做法。

with open("file1.txt", 'r') as f1:
        f1 =f1.read().split()

因为当您不使用with打开文件时，它将关闭该文件。Python非常擅长释放和管理内存，但确保释放它或调用它始终是一个好习惯。

file1.close()

当你完成的时候。

Answer 2

假设您希望逐字比较，比如a b c与b a c的比较会同时返回a和b，那么b和a (与原始代码中的None相反)

import string
import itertools

class FileExhausted(Exception): pass

def read_by_word(file):
    def read_word():
        while True:
            l = file.read(1)
            if l:
                if l in string.whitespace:
                    break
                yield l
            else:
                raise FileExhausted

    while True:
        this_word_gen = read_word()
        try:
            this_word = "".join(this_word_gen)
        except FileExhausted:
            break
        else:
            if this_word:
                yield this_word

def translation_comparison():
    with open("file1.txt") as file1, open("file2.txt") as file2:
        words1 = read_by_word(file1)
        words2 = read_by_word(file2)

        for (word1, word2) in itertools.zip_longest(words1, words2, fillvalue=None):
            if word1 != word2:
                yield (word1, word2)