提取Node.js jszip库

Question

我正在编写一些节点代码，并使用jszip压缩和解压缩一些文件。我知道如何压缩，但不知道如何解压缩或解压缩。堆栈溢出上有几个链接不起作用。有人找到解决办法了吗？以下是我尝试过的

var fs = require('fs');
var JSZip   = require('jszip');
var zipName = "C:/test.zip";
var unzip = "C:/unzip";


fs.readFile(zipName, function (err, data) {
    if (err) throw err;
    var zip = new JSZip();
    zip.folder(unzip).load(data);
});

Answer 1

JSZip没有在磁盘上写入文件的方法。为此，您需要在zip.files上进行迭代：

var path = require("path");
Object.keys(zip.files).forEach(function(filename) {
  var content = zip.files[filename].asNodeBuffer();
  var dest = path.join(unzip, filename);
  fs.writeFileSync(dest, content);
}

在zip文件中，文件夹用斜杠'/‘表示，我认为path.join()会创建正确的路径，但我不能测试这个路径。

Answer 2

可能是由于我对asNodeBuffer的错误实现和对JS缺乏经验，但我一直错误地提取文件。我想分享我的工作结果，我用一个250+ MB文件测试了它。

...
fs.readFile(tmpFilePath, function (err, data) {
    if (err) {
        throw err;
    }
    logger.debug('[method] Before extracting file...');
    JSZip.loadAsync(data).then(function (zip) {
        var files = Object.keys(zip.files);
        logger.debug('[method] files to be created ' + files.length);
        // in my case, the folders where not being created while "inflating" the content. created the folders in a separated loop 
        // O(n) for those geeks on complexity. 
        createDirectories(files);
        createFiles(files, zip, someOtherFunctionReference);
    }).catch(function (err) {
        deferred.reject(err);
    });
});
...

/**
 * Sync opperation to create the folders required for the files.
 * @param files
 */
function createDirectories(files) {
    files.forEach(function (filename) {
        var dest = path.join(folderName, filename);
        ensureDirectoryExistence(dest);
    });
}

/**
 * recursive create directory function
 * @param filePath
 * @returns {boolean}
 */
function ensureDirectoryExistence(filePath) {
    var dirname = path.dirname(filePath);
    if (fs.existsSync(dirname)) {
        return true;
    }
    ensureDirectoryExistence(dirname);
    fs.mkdirSync(dirname);
}

/**
 * Create files sync or blocking
 * @param files
 * @param zip
 * @param cb
 */
function createFiles(files, zip, cb) {
    try {
        var countFilesCreated = 0;
        files.forEach(function (filename) {
            var dest = path.join(folderName, filename);
            // skip directories listed
            if (dest.charAt(dest.length - 1) === '/') {
                countFilesCreated++;
                return;
            }
            return zip.file(filename).async('nodebuffer').then(function(content){
                // var content = zip.files[filename].nodeStream();
                fs.writeFileSync(dest, content);
                countFilesCreated++;
                // proably someone with more experience in JS can implement a promice like solution. 
                // I thought that in here instead of the counter we coud use an indexOf to return an error in case not all the elements where created correctly. 
                // but if a file throw an error, its handled by the catch ... 
                if (countFilesCreated >= files.length) {
                    logger.debug('All files created!!');
                    cb();
                }
            });
        });
    } catch (err) {
        throw err;
    }
}

我希望这能帮到你。