带有多个条件的Bash脚本if语句

Question

我正试图为一个流浪的傀儡开发env创建一个简单的bash shell脚本提供程序，它检查/tmp/pu偶最新模块是否存在，并且是在特定的时间框架内创建的，准确地说是14天。我正努力用这个简单的脚本来取得进展。任何帮助都很感激。

#!/bin/bash

if [[ ! -f /tmp/.puppet-modules-up-to-date ]] && [[ ! (find /tmp/.puppet-modules-up-to-date -mtime -14 | grep puppet) ]]; then

    puppet_dir=/etc/puppet

    echo 'Copying Puppetfile into place'
    cp /vagrant/puppet/Puppetfile $puppet_dir

    cd $puppet_dir

    echo 'Installing puppet modules into place'
    librarian-puppet install

    echo 'Updating previously installed puppet modules'
    librarian-puppet update 

    touch /tmp/.puppet-modules-up-to-date
fi

只需给出以下错误：

==> default: /tmp/vagrant-shell: line 3: conditional binary operator expected
==> default: /tmp/vagrant-shell: line 3: expected `)'
==> default: /tmp/vagrant-shell: line 3: syntax error near `/tmp/.puppet-modules-up-to-date'
==> default: /tmp/vagrant-shell: line 3: `if [[ ! -f /tmp/.puppet-modules-up-to-date ]] && [[ ! (find /tmp/.puppet-modules-up-to-date -mtime -14 | grep puppet) ]]; then'

Answer 1

问题似乎就在这里：

[[ ! (find /tmp/.puppet-modules-up-to-date -mtime -14 | grep puppet) ]];

因为这并不是真正捕获find/grep的输出，所以可以使用$(find...)命令来完成。

但是，您可以使用grep -q更好地处理这种情况。

find /tmp/.puppet-modules-up-to-date -mtime -14 | grep -vq puppet