我有初始数据帧:
r_id1 r_score1 rid2 r_score2
Rank
ID1 ID2
1 A-1 id-1 1.23 id-34 6.78
2 A-1 id-9 2.34 id-45 3.45
3 A-2 id-8 3.56 id-32 4.56
4 A-3 id-6 4.35 id-10 3.98
5 A-4 id-4 7.89 id-67 2.98我希望我的数据帧是(Result_df):
Score_R1 Score_R2
r_id1 r_score1 rid2 r_score2
ID1 ID2
1 A-1 id-1 1.23 id-34 6.78
2 A-1 id-9 2.34 id-45 3.45
3 A-2 id-8 3.56 id-32 4.56
4 A-3 id-6 4.35 id-10 3.98
5 A-4 id-4 7.89 id-67 2.98我的数据帧是多索引的,具有multiindex列。我试过这段代码
final_df.columns = [' '.join(col).strip() for col in final_df.columns.values]这给出了下面的输出
ID1 ID2 r_id1 r_score1 rid2 r_score2
1 A-1 id-1 1.23 id-34 6.78
2 A-1 id-9 2.34 id-45 3.45
3 A-2 id-8 3.56 id-32 4.56
4 A-3 id-6 4.35 id-10 3.98
5 A-4 id-4 7.89 id-67 2.98之后:
cols = final_df.columns.map(''.join)
lvl = 'Score_R' + cols.str.extract('(\d+)', expand=False)
final_df.columns = [lvl, cols]
final_df.to_csv("f.csv")输出为:
Score_R1 Score_R1 Score_R2 Score_R2
r_id1 r_score1 rid2 r_score2
ID1 ID2
1 A-1 id-1 1.23 id-34 6.78
2 A-1 id-9 2.34 id-45 3.45
3 A-2 id-8 3.56 id-32 4.56
4 A-3 id-6 4.35 id-10 3.98
5 A-4 id-4 7.89 id-67 2.98我需要组合具有相同名称的列标题
Score_R1 Score_R2
r_id1 r_score1 rid2 r_score2
ID1 ID2
1 A-1 id-1 1.23 id-34 6.78
2 A-1 id-9 2.34 id-45 3.45发布于 2020-09-01 14:37:12
对于MultiIndex in columns,您可以使用str.extract从列名中获取数字、添加前缀和最后分配回原始列
print (df.columns.tolist())
[('r_id1', ''), ('r_score1', ''), ('rid2', ''), ('r_score2', '')]
cols = df.columns.map(''.join)
print (cols.tolist())
['r_id1', 'r_score1', 'rid2', 'r_score2']
lvl = 'Score_R' + cols.str.extract('(\d+)', expand=False)
print (lvl)
Index(['Score_R1', 'Score_R1', 'Score_R2', 'Score_R2'], dtype='object')
df.columns = [lvl, cols]
print (df)
Score_R1 Score_R2
r_id1 r_score1 rid2 r_score2
ID1 ID2
1 A-1 id-1 1.23 id-34 6.78
2 A-1 id-9 2.34 id-45 3.45
3 A-2 id-8 3.56 id-32 4.56
4 A-3 id-6 4.35 id-10 3.98
5 A-4 id-4 7.89 id-67 2.98
df.columns = df.columns.map('_'.join)
print (df)
Score_R1_r_id1 Score_R1_r_score1 Score_R2_rid2 Score_R2_r_score2
ID1 ID2
1 A-1 id-1 1.23 id-34 6.78
2 A-1 id-9 2.34 id-45 3.45
3 A-2 id-8 3.56 id-32 4.56
4 A-3 id-6 4.35 id-10 3.98
5 A-4 id-4 7.89 id-67 2.98编辑:可以将第一级缺失的值替换为空字符串:
cols = df.columns.droplevel(-1)
lvl = 'Score_R' + cols.str.extract('(\d+)', expand=False)
print (lvl)
Index(['Score_R1', 'Score_R1', 'Score_R2', 'Score_R2'], dtype='object')
lvl = lvl.where(~lvl.duplicated(), '')
print (lvl)
Index(['Score_R1', '', 'Score_R2', ''], dtype='object')
df.columns = [lvl, cols]
print (df)
Score_R1 Score_R2
r_id1 r_score1 rid2 r_score2
ID1 ID2
1 A-1 id-1 1.23 id-34 6.78
2 A-1 id-9 2.34 id-45 3.45
3 A-2 id-8 3.56 id-32 4.56
4 A-3 id-6 4.35 id-10 3.98
5 A-4 id-4 7.89 id-67 2.98
print (df.columns)
MultiIndex([('Score_R1', 'r_id1'),
( '', 'r_score1'),
('Score_R2', 'rid2'),
( '', 'r_score2')],
)https://stackoverflow.com/questions/63681031
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