将从MySQL派生的数据从一个PHP移动到另一个

Question

我正在创建一个Android应用程序，其中我有一个登录页面，然后一个页面显示基于谁登录的数据。

登录页面如下：

    <?php
    include('listview.php');
    $hostname_localhost ="URL";
    $database_localhost ="project_test";
    $username_localhost ="user";
    $password_localhost ="pass";
    $localhost = mysql_connect($hostname_localhost,$username_localhost,$password_localhost)
    or
    trigger_error(mysql_error(),E_USER_ERROR);

    mysql_select_db($database_localhost, $localhost);

    $username = $_POST['username'];
    $password = $_POST['password'];
    $query_search = "select * from Employee where Emp_Email = '".$username."' AND Emp_Password = '".$password. "'";
    $userid = mysql_query("SELECT Group_ID FROM Employee where Emp_Email = '".$username."' AND Emp_Password = '".$password. "'");

    $query_exec = mysql_query($query_search) or die(mysql_error());
    $rows = mysql_num_rows($query_exec);
    //echo $rows;
     if(($rows == 0) || ($username == NULL)) { 
     echo "No Such User Found"; 
     }
     else  {
        echo "User Found";  
    }
    ?>

我的列表页面是：

<?php 
$con = $con = mysql_connect("URL","user","pass");

if (!$con)   {   die('Could not connect: ' . mysql_error());   }
mysql_select_db("project_nfc", $con);

$result = mysql_query("SELECT * FROM Employee");

while($row = mysql_fetch_assoc($result))   {    $output[]=$row;   }

print(json_encode($output));

mysql_close($con); 
?>

在变量$result中，我试图只显示与登录人员具有相同GroupID的员工。

所以：

$result =mysql_query(“从雇员中选择*)；

应该是这样的

$result =mysql_query(“Group_ID =‘.$userid.”)；

其中，$userid来自登录PHP页面并发送到列表视图页。

因此，基本上如何从登录到listview的用户那里发送Group_ID？我只想显示与登录用户具有相同Group_ID的员工。

下面是代码的Android端：

登录视图：

package dbtesting.example.com.testexternaldb;

import android.app.Activity;

import org.apache.http.client.ResponseHandler;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.ResponseHandler;
import org.apache.http.client.entity.UrlEncodedFormEntity;
        import org.apache.http.client.methods.HttpPost;
        import org.apache.http.impl.client.BasicResponseHandler;
        import org.apache.http.impl.client.DefaultHttpClient;
        import org.apache.http.message.BasicNameValuePair;
        import android.app.Activity;
        import android.app.AlertDialog;
        import android.app.ProgressDialog;
        import android.content.DialogInterface;
        import android.content.Intent;
        import android.os.Bundle;
        import android.view.View;
        import android.view.View.OnClickListener;
        import android.widget.Button;
        import android.widget.EditText;
        import android.widget.TextView;
        import android.widget.Toast;

import java.util.ArrayList;
import java.util.List;

public class LoginPage extends Activity {
    Button b;
    EditText et,pass;
    TextView tv;
    HttpPost httppost;
    StringBuffer buffer;
    HttpResponse response;
    HttpClient httpclient;
    List<NameValuePair> nameValuePairs;
    ProgressDialog dialog = null;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.login_layout);

        b = (Button)findViewById(R.id.Button01);
        et = (EditText)findViewById(R.id.username);
        pass= (EditText)findViewById(R.id.password);
        tv = (TextView)findViewById(R.id.tv);

        b.setOnClickListener(new OnClickListener() {
            @Override
            public void onClick(View v) {
                dialog = ProgressDialog.show(LoginPage.this, "",
                        "Validating user...", true);
                new Thread(new Runnable() {
                    public void run() {
                        login();
                    }
                }).start();
            }
        });
    }

    void login(){
        try{

            httpclient=new DefaultHttpClient();
            httppost= new HttpPost("http://URL/Android/check.php"); // make sure the url is correct.
            //add your data
            nameValuePairs = new ArrayList<NameValuePair>(2);
            // Always use the same variable name for posting i.e the android side variable name and php side variable name should be similar,
            nameValuePairs.add(new BasicNameValuePair("username",et.getText().toString().trim()));  // $Edittext_value = $_POST['Edittext_value'];
            nameValuePairs.add(new BasicNameValuePair("password",pass.getText().toString().trim()));
            httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
            //Execute HTTP Post Request
            response=httpclient.execute(httppost);
            // edited by James from coderzheaven.. from here....
            ResponseHandler<String> responseHandler = new BasicResponseHandler();
            final String response = httpclient.execute(httppost, responseHandler);
            System.out.println("Response : " + response);
            runOnUiThread(new Runnable() {
                public void run() {
                    tv.setText("Response from PHP : " + response);
                    dialog.dismiss();
                }
            });

            if(response.equalsIgnoreCase("User Found")){
                runOnUiThread(new Runnable() {
                    public void run() {
                        Toast.makeText(LoginPage.this,"Login Success", Toast.LENGTH_SHORT).show();
                    }
                });


                startActivity(new Intent(LoginPage.this, MainActivity.class));

            }else{
                showAlert();
            }

        }catch(Exception e){
            dialog.dismiss();
            System.out.println("Exception : " + e.getMessage());
        }
    }
    public void showAlert(){
        LoginPage.this.runOnUiThread(new Runnable() {
            public void run() {
                AlertDialog.Builder builder = new AlertDialog.Builder(LoginPage.this);
                builder.setTitle("Login Error.");
                builder.setMessage("User not Found.")
                        .setCancelable(false)
                        .setPositiveButton("OK", new DialogInterface.OnClickListener() {
                            public void onClick(DialogInterface dialog, int id) {
                            }
                        });
                AlertDialog alert = builder.create();
                alert.show();
            }
        });
    }
}

列表视图(2页)：

阿普科克托：

package dbtesting.example.com.testexternaldb;

        import android.util.Log;
        import org.apache.http.HttpEntity;
        import org.apache.http.HttpResponse;
        import org.apache.http.client.ClientProtocolException;
        import org.apache.http.client.methods.HttpGet;
        import org.apache.http.impl.client.DefaultHttpClient;
        import org.apache.http.util.EntityUtils;
        import org.json.JSONArray;
        import org.json.JSONException;

        import java.io.IOException;

public class ApiConnector {


    public JSONArray GetAllCustomers()
    {
        // URL for getting all customers


        String url = "http://URL/Android/listview.php";

        // Get HttpResponse Object from url.
        // Get HttpEntity from Http Response Object

        HttpEntity httpEntity = null;

        try
        {

            DefaultHttpClient httpClient = new DefaultHttpClient();  // Default HttpClient
            HttpGet httpGet = new HttpGet(url);

            HttpResponse httpResponse = httpClient.execute(httpGet);

            httpEntity = httpResponse.getEntity();



        } catch (ClientProtocolException e) {

            // Signals error in http protocol
            e.printStackTrace();

            //Log Errors Here



        } catch (IOException e) {
            e.printStackTrace();
        }


        // Convert HttpEntity into JSON Array
        JSONArray jsonArray = null;

        if (httpEntity != null) {
            try {
                String entityResponse = EntityUtils.toString(httpEntity);

                Log.e("Entity Response  : ", entityResponse);

                jsonArray = new JSONArray(entityResponse);

            } catch (JSONException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            }
        }

        return jsonArray;


    }


}

实际列表查看页：

package dbtesting.example.com.testexternaldb;

        import android.app.Activity;
        import android.os.AsyncTask;
        import android.support.v7.app.ActionBarActivity;
        import android.support.v7.app.ActionBar;
        import android.support.v4.app.Fragment;
        import android.os.Bundle;
        import android.view.LayoutInflater;
        import android.view.Menu;
        import android.view.MenuItem;
        import android.view.View;
        import android.view.ViewGroup;
        import android.os.Build;
        import android.widget.BaseAdapter;
        import android.widget.ListView;
        import android.widget.TextView;

        import org.json.JSONArray;
        import org.json.JSONException;
        import org.json.JSONObject;

public class MainActivity extends ActionBarActivity {

    private ListView GetAllCustomerListView;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        this.GetAllCustomerListView = (ListView) this.findViewById(R.id.GetAllCustomerListView);

        new GetAllCustomerTask().execute(new ApiConnector());


    }

    private void setListAdapter(JSONArray jsonArray)
    {
        this.GetAllCustomerListView.setAdapter(new GetAllCustomerListViewAdapter(jsonArray,this));
    }


    private class GetAllCustomerTask extends AsyncTask<ApiConnector,Long,JSONArray>
    {
        @Override
        protected JSONArray doInBackground(ApiConnector... params) {

            // it is executed on Background thread

            return params[0].GetAllCustomers();
        }

        @Override
        protected void onPostExecute(JSONArray jsonArray) {

            setListAdapter(jsonArray);



        }
    }
}

Answer 1

在您的第一个登录文件中，添加此代码，以便将group_id放入session var：

$userid = mysql_query("SELECT Group_ID FROM Employee where Emp_Email = '".$username."' AND Emp_Password = '".$password. "'");
if ($row = mysql_fetch_assoc($userid)) {
    session_start();
    $_SESSION['group_id'] = $row['Group_ID'];
}

在第二种情况下，你可以做这样的事情：

session_start();    
if (isset($_SESSION['group_id'])) {
    $result = mysql_query("SELECT * FROM Employee where group_id=".$_SESSION['group_id']." ");
    }else{
    $result = mysql_query("SELECT * FROM Employee");
    }

但是请停止使用mysql_它是不推荐的，将开发切换到PDO或mysqli

下面是一个指向的链接--如何在java中处理

因此，在登录视图中，您可以更改：

HttpClient httpclient;

至

public static DefaultHttpClient httpclient;

在上颈项改变中：

DefaultHttpClient httpClient = new DefaultHttpClient();  // Default HttpClient
            HttpGet httpGet = new HttpGet(url);

            HttpResponse httpResponse = httpClient.execute(httpGet);

至：

HttpGet httpGet = new HttpGet(url);
HttpResponse httpResponse = LoginPage.httpClient.execute(httpGet);

Answer 2

我不知道你的数据库是怎么来的，试试这个：

    <?php 
$con = $con = mysql_connect("URL","user","pass");

if (!$con)   {   die('Could not connect: ' . mysql_error());   }
mysql_select_db("project_nfc", $con);

$result = mysql_query("SELECT * FROM Employee where id_group=".$id_group." ");

while($row = mysql_fetch_assoc($result))   {    $output[]=$row;   }

print(json_encode($output));

mysql_close($con); 
?>

确保您有一个列名id_group并且有一个变量$id_group