如何显示company_name而不是company_id

Question

我有一个存储jobdescription的模型，还有一个将作业显示给外部世界的视图Jobdetails，但是当我想在company_id的视图整数上显示来自Company模型的company_name时，我遇到了一个问题。

我尝试过不同的方法，但还是没有用。

所以，我不知道如何在我的控制器中构建这个查询，如果你能告诉我问题出在哪里，那你就太好了。谢谢。

Schema.rb

ActiveRecord::Schema.define(version: 20150212182839) do


  create_table "companies", force: true do |t|
    t.string   "company_name"
    t.string   "user_id"
    t.datetime "created_at"
    t.datetime "updated_at"
  end

  create_table "jobdescriptions", force: true do |t|
    t.string   "applyjobid"
    t.string   "job_title"
    t.string   "department"
    t.text     "shift"
    t.string   "work_location"
    t.string   "position_supervisor"
    t.string   "supervisor_position_supervisor"
    t.decimal  "rate_pay"
    t.text     "benefits"
    t.text     "other_benefits"
    t.text     "job_summary"
    t.text     "job_duties"
    t.text     "tasks"
    t.text     "results"
    t.text     "responsibilities"
    t.text     "knowledge"
    t.text     "skills"
    t.text     "abilities"
    t.text     "physical_requirement"
    t.text     "work_envir_condition"
    t.text     "protective_clothing_and_devices_required"
    t.text     "tools_or_equipment_required"
    t.text     "qualifications"
    t.text     "education_and_training"
    t.text     "license_certification"
    t.text     "experience"
    t.text     "aptitudes_interests_temperament"
    t.text     "roles_relationships"
    t.text     "supervisory_responsibility"
    t.text     "advancement_promotion_opportunities"
    t.string   "internal_comment"
    t.string   "submited_by"
    t.string   "approved_by"
    t.string   "statut"
    t.date     "from_date"
    t.date     "end_date"
    t.integer  "company_id"
    t.datetime "created_at"
    t.datetime "updated_at"
  end

  add_index "jobdescriptions", ["company_id"], name: "index_jobdescriptions_on_company_id"

  create_table "users", force: true do |t|
    t.string   "username"
    t.string   "country"
    t.string   "role_id"
    t.integer  "company_id"
    t.string   "email", default: "", null: false
    t.string   "encrypted_password", default: "", null: false
    t.string   "reset_password_token"
    t.datetime "reset_password_sent_at"
    t.datetime "remember_created_at"
    t.integer  "sign_in_count", default: 0,  null: false
    t.datetime "current_sign_in_at"
    t.datetime "last_sign_in_at"
    t.integer  "current_sign_in_ip"
    t.integer  "last_sign_in_ip"
    t.datetime "created_at"
    t.datetime "updated_at"
  end

  add_index "users", ["company_id"], name: "index_users_on_company_id"

  add_index "users", ["email"], name: "index_users_on_email", unique: true

  add_index "users", ["reset_password_token"], name: "index_users_on_reset_password_token", unique: true

  create_table "users_roles", id: false, force: true do |t|
    t.integer "user_id"
    t.integer "role_id"
  end

  add_index "users_roles", ["user_id", "role_id"], name: "index_users_roles_on_user_id_and_role_id"

end

这是我的JobdescriptionsController

class JobdescriptionsController < ApplicationController
  layout 'application'

  def new
    @jobdescription = Jobdescription.new
  end

  def create
    @jobdescription = current_user.company_id.jobdescriptions.create(jobdescription_params)
    redirect_to new_jobdescription_path
  end

  private

    def jobdescription_params
        params.require(:jobdescription).permit(:applyjobid, :job_title, :work_location, :rate_pay, :shift, )
    end
end

Jobdetails Controller

 class JobdetailsController < ApplicationController
   layout 'apply'

       def show
         @jobdetail = Jobdescription.find_by_applyjobid(params[:applyjobid])
         @nm = @jobdetail.company_name
       end

   end

Jobdescription模型

  class Jobdescription < ActiveRecord::Base
    belongs_to :company
  end

Company模型

 class Company < ActiveRecord::Base
   has_many :users
   has_many :jobdescriptions
 end

视图Jobdetails/show

 <strong>Company name:</strong>
 <%= @nm %>

Answer 1

Jobdetail模型没有company_name方法，但Company有。只需更改@nm任务，通过公司协会获取公司名称：

@nm = @jobdetail.company.company_name

Answer 2

您可以在模型中添加company_name作为方法，就好像您多次使用它一样。

def company_name
 company.company_name
end

那么您就可以直接使用它了。

@jobdetail.company_name