在if(lr == 0)中,我收到了以下错误:“期待‘结束模块’,找到'if‘。Verilog代码是一个8位移位寄存器,充当左移位和右移位,可以在算术移位和逻辑移位之间进行选择。我看不出我为什么会收到这个错误。这可能是某种类型的语法错误,因为我对Verilog并不熟悉。谢谢事先提供的帮助。
module shifter(
input [7:0] shift_in,
input [2:0] shift_by,
// 0 for left, 1 for right
input lr,
//0 for logical, 1 for arithmetic
input arith,
output reg signed [7:0] shift_out
);
//left shift
if(lr == 0)
begin
assign shift_out = shift_in << shift_by;
assign shift_out[0] = 1'b0;
end
//right shift
else begin
//logical shift
if (arith == 0) begin
assign shift_out = shift_in << shift_by;
assign shift_out[7] = 1'b0;
//arithmetic shift
end else begin
assign shift_out[7] = shift_in[7];
assign shift_out = shift_in << shift_by;
end
end
endmodule发布于 2015-02-12 09:22:21
如果在赋值中使用这样的状态,则不能使用。放置在一个始终块,并删除分配。
always @* begin
//left shift
if(lr == 1'b0)
begin
shift_out = shift_in << shift_by;
shift_out[0] = 1'b0;
end
//right shift
else begin
//logical shift
if (arith == 0) begin
shift_out = shift_in << shift_by;
shift_out[7] = 1'b0;
//arithmetic shift
end else begin
shift_out[7] = shift_in[7];
shift_out = shift_in << shift_by;
end
end
endhttps://stackoverflow.com/questions/28471861
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