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Android Google登录
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Stack Overflow用户
提问于 2015-02-10 17:11:59
回答 1查看 125关注 0票数 0

我在登录Google时遇到了很多问题。我已经看到了许多可能的实现,但其中没有一个看起来真正有效。

这里是来自这里的#1

代码语言:javascript
复制
@Override
public void onConnected(Bundle bundle) {
    Log.d("MA", "onConnected");
    mSignInOut.setVisibility(View.VISIBLE);
    mSignInOut.setText(getResources().getText(R.string.signOut));
    mSignInOut.setTextColor(getResources().getColor(R.color.signOutButton));
    mLoggedInMessage.setText(getResources().getText(R.string.loggedInMessage) + " " + getUsername() + "!");
}



protected boolean isSignedIn() {
    return (mGoogleApiClient != null && mGoogleApiClient.isConnected());
}

public void signInOut() {
    if(isSignedIn()) {
        Log.d("MA", "signinout: signing out");
        mSignInClicked = false;
        Games.signOut(mGoogleApiClient);
        mGoogleApiClient.disconnect();
        onLoggedOut();
    } else {
        Log.d("MA", "signinout: signing in");
        mSignInClicked = true;
        mGoogleApiClient.connect();
    }
}

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    if (requestCode == RQC_SIGN_IN) {
        mResolvingError = false;
        if (resultCode == RESULT_OK) {
            // Make sure the app is not already connected or attempting to connect
            if (!mGoogleApiClient.isConnecting() &&
                    !mGoogleApiClient.isConnected()) {
                mGoogleApiClient.connect();
            }
        }
    }
@Override
public void onConnectionFailed(ConnectionResult result) {
    if (mResolvingError) {
        // Already attempting to resolve an error.
        return;
    } else if (result.hasResolution()) {
        try {
            mResolvingError = true;
            result.startResolutionForResult(this, RQC_SIGN_IN);
        } catch (IntentSender.SendIntentException e) {
            // There was an error with the resolution intent. Try again.
            mGoogleApiClient.connect();
        }
    } else {
        // Show dialog using GooglePlayServicesUtil.getErrorDialog()
        showErrorDialog(result.getErrorCode());
        mResolvingError = true;
    }
}

// The rest of this code is all about building the error dialog

/* Creates a dialog for an error message */
private void showErrorDialog(int errorCode) {
    // Create a fragment for the error dialog
    ErrorDialogFragment dialogFragment = new ErrorDialogFragment();
    // Pass the error that should be displayed
    Bundle args = new Bundle();
    args.putInt("DIALOG_ERROR", errorCode);
    dialogFragment.setArguments(args);
    dialogFragment.show(getSupportFragmentManager(), "errordialog");
}

/* Called from ErrorDialogFragment when the dialog is dismissed. */
public void onDialogDismissed() {
    mResolvingError = false;
}

/* A fragment to display an error dialog */
public static class ErrorDialogFragment extends DialogFragment {
    public ErrorDialogFragment() { }

    @Override
    public Dialog onCreateDialog(Bundle savedInstanceState) {
        // Get the error code and retrieve the appropriate dialog
        int errorCode = this.getArguments().getInt("DIALOG_ERROR");
        return GooglePlayServicesUtil.getErrorDialog(errorCode,
                this.getActivity(), RQC_SIGN_IN);
    }

    @Override
    public void onDismiss(DialogInterface dialog) {
        ((MainActivity)getActivity()).onDialogDismissed();
    }
}

这里的问题是,当我在应用程序启动后再次登录时,UI不会改变/ onConnected不会被调用,但是当我切换活动以便它再次尝试连接时,它会立即调用onConnected。当我将super.onActivityResult(requestCode, resultCode, data);放到onActivityResult的顶部时,它起了作用,但之后它连接起来了,在成功连接之后,他似乎再次尝试连接,但就在我选择帐户之前,窗口就消失了。编辑:而且,当出了问题时,它也不会显示任何错误对话框。

数字2是完全相同的,但是对于不同的onActivityResultonConnectionFailed方法,是从这里获得的。

代码语言:javascript
复制
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
   if (requestCode == RQC_SIGN_IN) {
        mSignInClicked = false;
        mResolvingError = false;
        Log.d("MA", "resultCode: " + resultCode);
        if (resultCode == RESULT_OK) {
            mGoogleApiClient.connect();
        } else {
            Log.d("MA", "onActivityResult, resultCode != -1");
            BaseGameUtils.showActivityResultError(this, requestCode, resultCode, R.string.signin_other_error);
        }
    }
@Override
public void onConnectionFailed(ConnectionResult result) {
    // If the sign in button was clicked or if auto sign-in is enabled,
    // launch the sign-in flow
    Log.d("BFA", "onConnectionFailed, connectionresult: " + result.getErrorCode());
    if (mResolvingError) {
        Log.d("BFA", "Already attempting to resolve an error.");
        // Already attempting to resolve an error.
        return;
    }
    if (mSignInClicked || mAutoLogin) {
        mResolvingError = true;
        mSignInClicked = false;
        mAutoLogin = false;
        if (!BaseGameUtils.resolveConnectionFailure(this, mGoogleApiClient, result,
                RQC_SIGN_IN, getString(R.string.signin_other_error))) {
            Log.d("MA", "resolveConnectionFailure false");
            mResolvingError = false;
        }
    }
}

使用这种方法,我在选择帐户后会收到一条错误消息,但是在选择帐户后,我还是会登录。

谁来帮帮我?

EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2015-02-10 21:00:32

好的,我终于发现了这个错误,当然,我最终会在那里搜索。

Builder的创建过程中,我使用了enableAutoManage(),所以它显然重复了我想要做的操作。停下来工作,使用一种类似于第二种方法。

票数 0
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/28437692

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