解析json

Question

我是安卓development.In的新手，我的应用程序我正在使用google从address.But中获取lat，我一直在解析json，因为我不知道如何解析这类json。

JSON

{
    "results": [
        {
            "address_components": [
                {
                    "long_name": "Kurla West",
                    "short_name": "Kurla West",
                    "types": [
                        "sublocality_level_2",
                        "sublocality",
                        "political"
                    ]
                },
                {
                    "long_name": "Mumbai",
                    "short_name": "Mumbai",
                    "types": [
                        "locality",
                        "political"
                    ]
                },
                {
                    "long_name": "Mumbai Suburban",
                    "short_name": "Mumbai Suburban",
                    "types": [
                        "administrative_area_level_2",
                        "political"
                    ]
                },
                {
                    "long_name": "Maharashtra",
                    "short_name": "MH",
                    "types": [
                        "administrative_area_level_1",
                        "political"
                    ]
                },
                {
                    "long_name": "India",
                    "short_name": "IN",
                    "types": [
                        "country",
                        "political"
                    ]
                }
            ],
            "formatted_address": "Kurla West, Mumbai, Maharashtra, India",
            "geometry": {
                "bounds": {
                    "northeast": {
                        "lat": 19.0894645,
                        "lng": 72.89236650000001
                    },
                    "southwest": {
                        "lat": 19.0587919,
                        "lng": 72.87059769999999
                    }
                },
                "location": {
                    "lat": 19.0707532,
                    "lng": 72.8781322
                },
                "location_type": "APPROXIMATE",
                "viewport": {
                    "northeast": {
                        "lat": 19.0894645,
                        "lng": 72.89236650000001
                    },
                    "southwest": {
                        "lat": 19.0587919,
                        "lng": 72.87059769999999
                    }
                }
            },
            "types": [
                "sublocality_level_2",
                "sublocality",
                "political"
            ]
        }
    ],
    "status": "OK"
}

我试过的密码。

jsonObject = new JSONObject(response);

                            if (jsonObject.get("results") instanceof JSONObject) {


                            } else if (jsonObject.get("results") instanceof JSONArray) {
                                jsonArray = jsonObject.getJSONArray("results");

                                for (int j = 0; j < jsonArray.length(); j++) {
                                    jsonObject = jsonArray.getJSONObject(i);

                                    latitude = jsonObject.getJSONObject("location").getDouble("lat");
                                }
                            }



                        } catch (JSONException f) {

                            Log.e("Json exception", f.getMessage());


                        }

例外

No value for location

请帮助我解析这个json，谢谢

Answer 1

你忘了几何学

jsonArray = jsonObject.getJSONArray("results");
for (int j = 0; j < jsonArray.length(); j++) {
jsonObject = jsonArray.getJSONObject(i); 

latitude=jsonObject.getJSONObject("geometry").getJSONObject("location").getDouble("lat");
} 

Answer 2

try {
        JSONObject jObject = new JSONObject(response);
        JSONArray jResults = jObject.getJSONArray("results");
        JSONObject jPlaceObj = jResults.getJSONObject(0);
        JSONObject jGeometry =  jPlaceObj.getJSONObject("geometry");
        JSONObject jLocation = jGeometry.getJSONObject("location");

        String lat = jLocation.getString("lat");
        String lng = jLocation.getString("lng");

    } catch (JSONException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

其中' response‘是来自的字符串中的JSON响应。如果您需要的话，我没有添加转换代码，请告诉我。

Answer 3

根是这里的一个对象。所以,

JSONObject root=new JSONObject(result);// result is JSON string

“结果”是一个数组。所以,

JSONArray resultArray=root.getJSONArray("results");

你需要lat和lang的价值。所以,

JSONObject locationObj=resultArray.getJSONObect("location");

Double lat=locationObj.getDouble("lat");

Double lng=locationObj.getDouble("lng");

如果结果只有一个位置，您可以直接使用上面的代码。如果结果中有许多地方，则创建一个Location模型类。宣布lat和lang为属性。并将值保存到位置的ArrayList中。