我试图在一个名为"post-info.php“的php文件中编写一个数组,如下所示:
<?php
$settings = array(
'submitter' => 'tester',
'body' => "How about this:
> Gigabyte Tri-SLI Liquid Luggage 980s",
);
?>首先,我希望body是一个多行变量。然后,我希望它被一个index.php文件调用,通过一个Markdown解析器,然后显示出来。看起来有点像这样:
<!DOCTYPE html>
<?php
include 'Parsedown.php';
$postinfo = include 'post-info.php';
$Parsedown = new Parsedown();
?>
<html lang="en">
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<link href="bootstrap/css/bootstrap.min.css" rel="stylesheet">
<link href="style.css" rel="stylesheet">
</head>
<body>
<div class="container">
<div class="jumbotron vertical-center">
<blockquote>
<div class="post-body"><?php echo $Parsedown->text($postinfo["body"]); ?></div>
<hr />
<p class="post-submitter"><?php include($postinfo["submitter"]); ?></p>
</blockquote>
</div>
</div>
</body>
</html>那么,如何让这两个变量出现在这些地方(毫无疑问,我写错了),让多行变量实际显示多行呢?
发布于 2015-02-10 00:30:10
我不知道Parsedown.php,但对于原始php,如果您使用
include 'post-info.php';
//then you can use your $settings variable defined in post-info.php
echo $Parsedown->text($settings["body"]);发布于 2015-02-10 00:29:48
而不是这个
<p class="post-submitter"><?php include($postinfo["submitter"]); ?></p>试着用这个
<p class="post-submitter"><?= $settings["submitter"]; ?></p>https://stackoverflow.com/questions/28421951
复制相似问题