如何在java中将多层xml简化为List<String xpath >？

Question

其目的是在叶级将多级重复的xml扁平化为xpath；这样我们就可以将它存储在键值存储中并检索它。假设每个重复节点都有一个UID。

1. 生成一个成对列表，其中键为"XPATH“，值为该叶的实际值。
2. 应该能够将其组装回xml中。
3. xml由xsd支持(有JAXB解决方案吗)

编辑并用一个更简单的xml替换了以前的xml。

示例xml如下所示

<?xml version="1.0" encoding="UTF-8"?>
<cars>
    <car uid="WxiMr123">
        <carDoor uid="WRP2">
            <location uid="loc-1">
                <width uom="ft">2</width>
                <height uom="ft">3</height>
            </location>
            <location uid="loc-2">
                <width uom="m">5</width>
                <height uom="m">7</height>
            </location>
        </carDoor>
        <commonData>
            <timeCreated>2001-04-30T08:15:00.000Z</timeCreated>
        </commonData>        
    </car>    
</cars>

我看到的xpath K，V对应该看起来像

/cars/car[@uid="WxiMr123"]@uid , "WxiMr123"
/cars/car[@uid="WxiMr123"]/carDoor[@uid="WRP2"]@uid, "WRP2"
/cars/car[@uid="WxiMr123"]/carDoor[@uid="WRP2"]/location[@uid="loc-1"]@uid, "loc-1"
/cars/car[@uid="WxiMr123"]/carDoor[@uid="WRP2"]/location[@uid="loc-1"]/width[@uom="ft"]@uom, "ft"
/cars/car[@uid="WxiMr123"]/carDoor[@uid="WRP2"]/location[@uid="loc-1"]/width[@uom="ft"]/text(), "2"
/cars/car[@uid="WxiMr123"]/carDoor[@uid="WRP2"]/location[@uid="loc-1"]/height[@uom="ft"]@uom, "ft"
/cars/car[@uid="WxiMr123"]/carDoor[@uid="WRP2"]/location[@uid="loc-1"]/height[@uom="ft"]/text(), "3"
/cars/car[@uid="WxiMr123"]/carDoor[@uid="WRP2"]/location[@uid="loc-2"]@uid, "loc-2"
/cars/car[@uid="WxiMr123"]/carDoor[@uid="WRP2"]/location[@uid="loc-2"]/width[@uom="m"]@uom, "m"
/cars/car[@uid="WxiMr123"]/carDoor[@uid="WRP2"]/location[@uid="loc-2"]/width[@uom="m"]/text(), "5"
/cars/car[@uid="WxiMr123"]/carDoor[@uid="WRP2"]/location[@uid="loc-2"]/height[@uom="m"]@uom, "m"
/cars/car[@uid="WxiMr123"]/carDoor[@uid="WRP2"]/location[@uid="loc-2"]/height[@uom="m"]/text(), "7"
/cars/car[@uid="WxiMr123"]/commonData/timeCreated/text(), "2001-04-30T08:15:00.000Z"

任何帮助都是非常感谢的。

Answer 1

制作所需的文件并不那么困难。例如，以下样式表：

XSLT1.0

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" encoding="UTF-8"/>
<xsl:strip-space elements="*"/>

<xsl:template match="/">
    <xsl:for-each select="//text() | //@*[string()]">
        <xsl:for-each select="ancestor::*">
            <xsl:value-of select="concat('/', name())" />
                <xsl:for-each select="@*">
                    <xsl:value-of select="concat('[@', name(), '=&quot;', ., '&quot;]')" />
                </xsl:for-each>
        </xsl:for-each>
        <xsl:choose>
            <xsl:when test="name()">
                <xsl:value-of select="concat('/@', name())" />
            </xsl:when>
            <xsl:otherwise>/text()</xsl:otherwise>
        </xsl:choose>
        <xsl:value-of select="concat(', &quot;', ., '&quot;&#10;')" />
    </xsl:for-each>
</xsl:template>

</xsl:stylesheet>

当应用于示例输入时，将生成以下结果

/cars/car[@uid="WxiMr123"]/@uid, "WxiMr123"
/cars/car[@uid="WxiMr123"]/carDoor[@uid="WRP2"]/@uid, "WRP2"
/cars/car[@uid="WxiMr123"]/carDoor[@uid="WRP2"]/location[@uid="loc-1"]/@uid, "loc-1"
/cars/car[@uid="WxiMr123"]/carDoor[@uid="WRP2"]/location[@uid="loc-1"]/width[@uom="ft"]/@uom, "ft"
/cars/car[@uid="WxiMr123"]/carDoor[@uid="WRP2"]/location[@uid="loc-1"]/width[@uom="ft"]/text(), "2"
/cars/car[@uid="WxiMr123"]/carDoor[@uid="WRP2"]/location[@uid="loc-1"]/height[@uom="ft"]/@uom, "ft"
/cars/car[@uid="WxiMr123"]/carDoor[@uid="WRP2"]/location[@uid="loc-1"]/height[@uom="ft"]/text(), "3"
/cars/car[@uid="WxiMr123"]/carDoor[@uid="WRP2"]/location[@uid="loc-2"]/@uid, "loc-2"
/cars/car[@uid="WxiMr123"]/carDoor[@uid="WRP2"]/location[@uid="loc-2"]/width[@uom="m"]/@uom, "m"
/cars/car[@uid="WxiMr123"]/carDoor[@uid="WRP2"]/location[@uid="loc-2"]/width[@uom="m"]/text(), "5"
/cars/car[@uid="WxiMr123"]/carDoor[@uid="WRP2"]/location[@uid="loc-2"]/height[@uom="m"]/@uom, "m"
/cars/car[@uid="WxiMr123"]/carDoor[@uid="WRP2"]/location[@uid="loc-2"]/height[@uom="m"]/text(), "7"
/cars/car[@uid="WxiMr123"]/commonData/timeCreated/text(), "2001-04-30T08:15:00.000Z"

Note

1. 这可能不是最有效的方法；对于大型XMl文档，最好应用模板/s递归遍历整个树；
2. 元素可能具有多个属性；您的示例没有说明如何在构建路径时处理这些属性；
3. 元素可能位于名称空间中；您的示例没有说明如何处理这些元素；
4. 空节点被排除在外；如果您试图从此转换的结果中重构原始XML文档(我不知道如何实现)，这些节点就会丢失。