Java减法LocalTime

Question

我有两个LocalTime对象：

LocalTime l1 = LocalTime.parse("02:53:40");
LocalTime l2 = LocalTime.parse("02:54:27");

我怎么能在几分钟内发现他们之间的不同？

Answer 1

使用until或between，如api接口所述

import java.time.LocalTime;
import static java.time.temporal.ChronoUnit.MINUTES;

public class SO {
    public static void main(String[] args) {
        LocalTime l1 = LocalTime.parse("02:53:40");
        LocalTime l2 = LocalTime.parse("02:54:27");
        System.out.println(l1.until(l2, MINUTES));
        System.out.println(MINUTES.between(l1, l2));
    }
}

0 0 0

Answer 2

从Java 8开始，您可以使用Duration类。我认为这是最优雅的解决方案：

long elapsedMinutes = Duration.between(l1, l2).toMinutes();

Answer 3

我用 ChronoUnit做这件事

long minutesBetween = ChronoUnit.MINUTES.between(l1,l2);

示例

    LocalTime localTime=LocalTime.now();
    LocalTime localTimeAfter5Minutes=LocalTime.now().plusMinutes(5);
    Long minutesBetween=ChronoUnit.MINUTES.between(localTime,localTimeAfter5Minutes);
    System.out.println("Diffrence between time in munutes : "+minutesBetween);

输出

Diffrence between time in munutes : 5