jclouds labs获取一个ComputeService对象

Question

使用Jclouds和jclouds，我有下面的代码片段--它正在按预期工作

ContextBuilder contextBuilder = ContextBuilder.newBuilder(cloudProvider);

AzureComputeApi api = contextBuilder
     .credentials(keyStoreLocation, keyStorePassword)
     .endpoint(uri + subscriptionId)
     .buildApi(AzureComputeApi.class);

List<Location> locations = api.getLocationApi().list();
for(Location l : locations)
     System.out.println(l);

AzureComputeApi正在连接和打印预期输出

Location{name=West Europe, displayName=West Europe, availableServices=[Compute, Storage, PersistentVMRole, HighMemory]}
Location{name=North Europe, displayName=North Europe, availableServices=[Compute, Storage, PersistentVMRole, HighMemory]}
...

但是，我现有的jclouds代码库使用的是ComputeService类型，例如，这种方法正在运行cloudProvider的AWS和GCE

ContextBuilder contextBuilder = newContextBuilder(cloudProvider);

ComputeService cs =  contextBuilder
    .credentials(identity, credential)
    .buildView(ComputeServiceContext.class)
    .getComputeService();

我如何让AzureComputeApi返回一个ComputeService (或类似的东西)，这样我就不必更改我现有的代码库了。

这是可能的吗。

如果我尝试这个代码片段-it，使用cloudPprovider=azurecompute

ContextBuilder contextBuilder = ContextBuilder.newBuilder(cloudProvider);
ComputeService cs  = contextBuilder
    .credentials(keyStoreLocation, keyStorePassword)
    .endpoint(uri + subscriptionId)
    .buildView(ComputeServiceContext.class)
    .getComputeService();

我会抛出这个异常

Exception in thread "main" java.lang.IllegalArgumentException: api {id=azurecompute, name=Microsoft Azure Service Management Service API, views=[], endpointName=Service Management Endpoint ending in your Subscription Id, identityName=Path to Management Certificate .p12 file, or PEM string, credentialName=Optional.of(Password to Management Certificate), documentation=http://msdn.microsoft.com/en-us/library/ee460799, api=interface org.jclouds.azurecompute.AzureComputeApi} not wrappable as org.jclouds.compute.ComputeServiceContext; context: org.jclouds.rest.ApiContext<org.jclouds.azurecompute.AzureComputeApi>, views: []
    at org.jclouds.ContextBuilder.buildView(ContextBuilder.java:604)
    at org.jclouds.ContextBuilder.buildView(ContextBuilder.java:588)
    at com.hazelcast.stabilizer.provisioner.ComputeServiceBuilder.main(ComputeServiceBuilder.java:79)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
    at java.lang.reflect.Method.invoke(Method.java:606)
    at com.intellij.rt.execution.application.AppMain.main(AppMain.java:120)

我知道我所有的keyStoreLocation，keyStorePassword，uri + subscriptionId变量都很好，因为如果我直接处理AzureComputeApi的话，它们就可以工作了。

Answer 1

Azure计算仍在开发中，ComputeService抽象仍在进行中，因此您还不能使用它；您必须直接使用AzureComputeApi。您可以跟踪JCLOUDS-664，如果您想要保持最新的。