使用JS/jQuery获取数组中对象的位置

Question

让我们假设我有一个数组如下：

[
    {
        "name": "list",
        "text": "SomeText1"
    },
    {
        "name": "complex",
        "text": "SomeText2",
        "config": {
            "name": "configItem",
            "text": "SomeText3",
            "anotherObject": {
                "name": "anotherObject1",
                "text": "SomeText4"
            }
        }
    }
]

我正在使用这个很棒的代码来获取具有特定密钥(http://techslides.com/how-to-parse-and-search-json-in-javascript)的所有对象。在我的示例中，由于文本作为键的外观，getObjects(data,'text','')将将所有节点作为对象返回。

我唯一的问题是，我需要知道返回对象在整个数组中的位置。

有什么办法可以得到吗？或者至少与数组相关联的对象的深度？

getObjects(r,'text','')[0] (name = list) ->深度1

getObjects(r,'text','')[1] (name = complex) ->深度1

getObjects(r,'text','')[2] (name = configItem) ->深度2

Answer 1

你需要这样的东西：

function getObjectsDepth(obj, key, val, depth) {
    var objects = [];
    for (var i in obj) {
        if (!obj.hasOwnProperty(i)) continue;
        if (typeof obj[i] == 'object') {
            objects = objects.concat(getObjectsDepth(obj[i], key, val,++depth));    
        } else 
        //if key matches and value matches or if key matches and value is not passed (eliminating the case where key matches but passed value does not)
        if (i == key && obj[i] == val || i == key && val == '') { //
            objects.push(depth);
        } else if (obj[i] == val && key == ''){
            //only add if the object is not already in the array
            if (objects.lastIndexOf(obj) == -1){
                objects.push(depth);
            }
        }
    }
    return objects;
}

这将返回对象的深度，而不是对象本身，只是根据您想要的计数方式传递0或1作为最后一个param。如果同时需要对象和深度，则需要obj.push({'obj':obj,'depth':depth})。

Answer 2

通过以下方法更改getObjects函数：

function getObjects(obj, key, val, depth) {
    var objects = [];
    depth = typeof depth !== 'undefined' ? depth : 0;
    for (var i in obj) {
        if (!obj.hasOwnProperty(i)) continue;
        if (typeof obj[i] == 'object') {
            depth ++;
            objects = objects.concat(getObjects(obj[i], key, val, depth));    
        } else 
        //if key matches and value matches or if key matches and value is not passed (eliminating the case where key matches but passed value does not)
        if (i == key && obj[i] == val || i == key && val == '') { //
            objects.push({"obj":obj,"depth": depth});
        } else if (obj[i] == val && key == ''){
            //only add if the object is not already in the array
            if (objects.lastIndexOf(obj) == -1){
                objects.push({"obj":obj,"depth": depth});
            }
        }
    }
    return objects;
} 

现在你得到了深度和物体。