解析python中的大型字符串

Question

我正试图解析一个字符串，提取特定的单词。

弦

{{About|the ALGOL-like programming language|the scripting language formerly named Small|Pawn (scripting language)}}

'''SMALL''', Small Machine Algol Like Language, is a [[computer programming|programming]] [[programming language|language]] developed by Dr. [[Nevil Brownlee]] of [[Auckland University]].

==History==
The aim of the language was to enable people to write [[ALGOL]]-like code that ran on a small machine.  It also included the '''string''' type for easier text manipulation.

SMALL was used extensively from about 1980 to 1985 at [[Auckland University]] as a programming teaching aid, and for some internal projects.  Originally written to run on a [[Burroughs Corporation]] B6700 [[Main frame]] in [[Fortran]] IV, subsequently rewritten in SMALL and ported to a DEC [[PDP-10]] Architecture (on the [[Operating System]] [[TOPS-10]]) and IBM S360 Architecture (on the Operating System VM/[[Conversational Monitor System|CMS]]).

About 1985, SMALL had some [[Object-oriented programming|object-oriented]] features added to handle structures (that were missing from the early language), and to formalise file manipulation operations.

==See also==
*[[ALGOL]]
*[[Lua (programming language)]]
*[[Squirrel (programming language)]]

==References==
*[http://www.caida.org/home/seniorstaff/nevil.xml Nevil Brownlee]

[[Category:Algol programming language family]]
[[Category:Systems programming languages]]
[[Category:Procedural programming languages]]
[[Category:Object-oriented programming languages]]
[[Category:Programming languages created in the 1980s]] 

我想从另一节中提取ALGOL、Lua (编程语言)、Squirrel(编程语言)。(确切地说，这些词不加括号或星号。)

我尝试过这些方法

字符串拆分正则表达式。我仍然无处可寻，帮助感激。

我用的代码

import urllib.request,json,re

url = "http://en.wikipedia.org/w/api.php?format=json&action=query&titles=SMALL&prop=revisions&rvprop=content"
response = urllib.request.urlopen(url)
str_response = response.readall().decode('utf-8')
obj = json.loads(str_response)
a=str(obj['query']['pages']['1808130']['revisions'][0]['*'])
print(a)

字符串存储在。

Answer 1

如果我正确理解，您需要==See also==和==References==之间的字符(不包括这些*[] )。我将您的初始字符串命名为my_string。

import re

# Sliced_string will only contain the characters between '==See also==' and '==References=='
sliced_string = re.findall(r'==See also==(.*?)==References==', my_string, re.DOTALL)[-1]

# Removes stars and brackets
for unwanted_char in '[]*':
    sliced_string = sliced_string.replace(unwanted_char, '')

# Creates a list of strings (also removes empty strings)
final_list = sliced_string.split('\n')
final_list = [elem for elem in final_list if elem != '']

print(final_list)

编辑：将字符串转换为列表。

假定给定字符串中只有==See also==和==References==的一次出现，代码就能正确工作。

Answer 2

print  re.findall(r"\*\[\[([^\]]*)\]\]",re.findall(r"==See also==((?:\s+\*\[\[(?:[^\]]*)\]\])+)",x)[0])

直接应用这一点，并发送存储在x中的字符串。