Python 3并发循环

Question

while True:
    name = input('Enter Texture Pack Name- ')
    name_length = len(name)

    if len(name) <= 0:
        print ('You didnt write anything, try again.')

    if len(name) == 1:
        print ('Thats not enough, try again.')

    if len(name) >= 18:
        print ('Thats to much, try again.')    

    if int(name_length) >= 2:
        break

print (('Texture Pack- %s') % (name))

所以我试图对名字的描述做两个限制，它太小，太大。我将中断设置为>= 2，所以任何超过18最大值的限制都会被打破。只有在长度大于2，但小于18的情况下，我才会告诉它断裂？

Answer 1

首先，我看到了一些问题。

并不是所有的代码都在while循环中。所有if语句都应该在while循环中，只需缩进这些语句即可。这可能是它应该看起来的样子：

while True:
    name = input("Enter Texture Pack Name- ")
    name_length = len(name)

    if name_length <= 0 or >=18:
        print("There's an error!")
        break
    else:
        print("texture pack- %s" % (name)

希望这能帮上忙。正如您所知，break必须在一个循环内。

编辑:丢弃顶部。我要重写这个！

while True:
    try:
        name = input("Enter texture pack name: ")
        name_length = int(len(name))
    if name_length <= 0:
        raise ValueError("Nothing was written!")
    elif name_length == 1:
        raise ValueError("Only one character!")
    elif name_length >= 18:
        raise ValueError("More than 18!")
    else:
        break
print ("Texture pack: %s" % (name))

这将继续要求正确的输入，直到它得到正确的。

Answer 2

试试这个：

name = input('Enter Texture Pack Name- ')
while len(name) <= 2 or len(name) >= 18:
    print('Error - texture pack name length should be between 2 and 17 characters')
    name = input('Enter Texture Pack Name- ')