我找不到错误,当我跑的时候,我得到了一个空白框
我正在尝试制作一个applet,您看到的第一个屏幕包含4个按钮,每个排序算法我必须实现一个按钮,然后一旦单击按钮,它就会带您到一个新面板,该面板具有数组排序的图形表示(我已经在一个较小的applet中这样做了)。
这是我的代码:
import java.awt.*;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.*;
public class newCLayoutTest extends JPanel{
private JPanel holderPanel, mainPanel, bubblePanel, selectionPanel, mergePanel, quickPanel;
private JButton bubbleButton, selectionButton, mergeButton, quickButton;
private CardLayout cardLayout = new CardLayout();
public newCLayoutTest()
{
JLabel label = new JLabel("Label");
holderPanel = new JPanel();
mainPanel = new JPanel();
bubblePanel = new JPanel();
selectionPanel = new JPanel();
mergePanel = new JPanel();
quickPanel = new JPanel();
holderPanel.setLayout(cardLayout);
bubbleButton = new JButton();
selectionButton = new JButton();
mergeButton = new JButton();
quickButton = new JButton();
//mainPanel.setLayout(new GridLayout(2,2));
mainPanel.add(bubbleButton);
mainPanel.add(selectionButton);
mainPanel.add(mergeButton);
mainPanel.add(quickButton);
bubblePanel.add(label);
holderPanel.add(mainPanel, "1");
holderPanel.add(bubblePanel, "2");
cardLayout.show(holderPanel,"2");
}
}控制器类:
import java.awt.BorderLayout;
import javax.swing.JFrame;
import javax.swing.SwingUtilities;
public class testControl extends JFrame{
/**
*
*/
private static final long serialVersionUID = 1L;
public static void main(String[] args){
SwingUtilities.invokeLater(new Runnable() {
public void run() {
newCLayoutTest panel = new newCLayoutTest();
JFrame frame = new JFrame("LET THIS WORK");
// frame.setLayout(new BorderLayout());
frame.add(panel);
//frame.getContentPane().add(panel);
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.setSize(600, 400);
frame.setVisible(true);
}
});
}
}发布于 2015-01-22 15:54:37
holderPanel尚未添加到包含组件的面板中,即newCLayoutTest
add(holderPanel);注意,没有必要对JPanel进行子类,因为您没有向面板添加任何新功能。您可以简单地创建一个面板并添加组件。还遵循Java命名约定,即对类名使用大写首字母,例如NewCLayoutTest。
https://stackoverflow.com/questions/28093014
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