String sql = "set @row \\:=-1; SELECT ue.id, ue.Latitude, ue.Longitude, ue.Serving_Cell, ue.RSCP
FROM ue INNER JOIN(
SELECT id
from (
SELECT @row \\:=@row+1 as rownum, id
from (
select id from ue order by id) as sorted
)as ranked
where rownum %20=0) as subset
on subset.id = ue.id
where Operator like :operator ";
Query query = getSessionFactory().getCurrentSession().createSQLQuery(sql);
query.setParameter("operator", "%" + operator + "%");
return query.list();请帮助我找到我的SQL错误控制台呈现给我:Servlet.service: Servlet.service() for servlet dispatcher在上下文中与路径/SpringSecurity抛出异常请求处理失败;嵌套异常是org.hibernate.exception.SQLGrammarException:无法从根本原因提取ResultSet,您的sql语法中有错误;检查与MySQL服务器版本对应的手册,以获得在第1行 'SELECT ue.id、ue.Latitude、ue.Longitude、ue.Serving_Cell、ue.RSCP FROM ue INNER‘附近使用的正确语法。
发布于 2015-01-19 14:21:52
您尝试一次执行两个查询。一次只能执行一个。
SELECT ue.id, ue.Latitude, ue.Longitude, ue.Serving_Cell, ue.RSCP
FROM ue INNER JOIN(
SELECT id
from (
SELECT @row \\:=@row+1 as rownum, id
from (
select id, @row
from ue, (select @row := -1) r
order by id) as sorted
)as ranked
where rownum %20=0) as subset
on subset.id = ue.id
where Operator like :operator但是,您可以使用子查询来初始化这样的变量
(select @row := -1) rhttps://stackoverflow.com/questions/28026725
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