通过Makefile编译2个文件不起作用

Question

我想一次编译两个.cpp文件。gstapp.cpp正在编译，gnew.cpp被忽略。我在看什么？

Makefile：

# generated from pkg-config --cflags gstreamer-0.10
CFLAGS=-pthread -I/usr/include/gstreamer-0.10 -I/usr/include/glib-2.0 -I/usr/lib/glib-2.0/include -I/usr/include/libxml2 

# generated from pkg-config --libs gstreamer-0.10
LDFLAGS=-lgstreamer-0.10 -lgobject-2.0 -lgmodule-2.0 -pthread -lgthread-2.0 -pthread -lglib-2.0 -lxml2 -lgstapp-0.10     

CFLAGS+=-I/usr/include/opencv2

# there are more, but not needed form now: -lopencv_calib3d -lopencv_contrib -lopencv_flann -lopencv_obj 
LDFLAGS+=-lstdc++ -lopencv_core -lopencv_features2d -lopencv_gpu -lopencv_highgui -lopencv_imgproc -lopencv_legacy -lopencv_ml -lopencv_nonfree -lopencv_video

gstapp: gstapp.o
    gcc $(LDFLAGS) -o $@ $<

gstapp.o: gstapp.cpp
    gcc -c $(CFLAGS) -o $@ $<

gnew: gnew.o
    gcc $(LDFLAGS) -o $@ $<

gnew.o: gnew.cpp
    gcc -c $(CFLAGS) -o $@ $<

Answer 1

您可能需要一个all规则来触发两者的编译。通过只运行没有参数的make，它将运行遇到的第一个规则(例如，gstapp:)，然后退出。

所以在LDFLAGS和gstapp之间

all: gstapp gnew

第一个规则(也称为默认规则)将在运行make或make all时将两个文件都作为依赖项进行编译。