bash脚本for循环，在每个输出中添加html标记

Question

为了添加td、/td等html标记(基本上是从输出构建一个表)，我在for循环中使用sed：

for host in `cat hostlist`;do echo "$host " | sed 's|\(.*\)|<tr><td>\1</td>|'; cat $host | grep "CPU util" | grep " [5-9][0-9]%" | sed 's|\(.*\)|<td>\1</td></tr>|'; done

输出无sed：

switch1

switch2
Core 0: CPU utilization for five seconds: 56%; one minute: 11%; five minutes: 8%
Core 0: CPU utilization for five seconds: 56%; one minute: 11%; five minutes: 8%
CPU utilization for five seconds: 63%; one minute: 23%;  five minutes: 18%
switch3
CPU utilization for five seconds: 78%/0%; one minute: 43%; five minutes: 40%

输出使用sed：

<tr><td>switch1 </td>
<tr><td>switch2 </td>
<td>Core 0: CPU utilization for five seconds: 56%; one minute: 11%; five minutes: 8%</td></tr>
<td>Core 0: CPU utilization for five seconds: 56%; one minute: 11%; five minutes: 8%</td></tr>
<td>CPU utilization for five seconds: 63%; one minute: 23%;  five minutes: 18%</td></tr>
<tr><td>switch3 </td>
<td>CPU utilization for five seconds: 78%/0%; one minute: 43%; five minutes: 40%</td></tr>

这不会将标记添加到空行，如switch1下面的一行(当grep返回0时)，对于开关2，我希望在一个表单元格中的所有外部单元格如下所示：

期望产出：

<tr><td>switch1 </td>
<td></td></tr>
<tr><td>switch2 </td>
<td>Core 0: CPU utilization for five seconds: 56%; one minute: 11%; five minutes: 8%<brZ
Core 0: CPU utilization for five seconds: 56%; one minute: 11%; five minutes: 8%<br>
CPU utilization for five seconds: 63%; one minute: 23%;  five minutes: 18%</td></tr>
<tr><td>switch3 </td>
<td>CPU utilization for five seconds: 78%/0%; one minute: 43%; five minutes: 40%</td></tr>

有什么建议吗？谢谢。

Answer 1

awk '/CPU util/{
    print "<td>" $0 "</tr>"
} 
!/CPU util/ {
    if ($1 == "")
        print "<tr><td>" $0 "</tr>"
    else 
        print "<tr><td>" $0 "</td>"
}' file_name`

会帮你做这件事。因为我测试了它，而且它看起来很有效，所以我决定回答而不是评论。