我有一个使用javax.ws.rs的twitter请求
WebTarget target = new WebTargetBuilder(client, OAUTH_API_ENDPOINT).build();
Builder request = target
.request(MediaType.APPLICATION_JSON)
.header("Authorization", "Basic " + encodedCredentials)
.header("Content-Type", "application/x-www-form-urlencoded;charset=UTF-8");
Response postResponse = request
.post(Entity.entity("grant_type=client_credentials", MediaType.TEXT_PLAIN));
System.out.println(postResponse.readEntity(String.class));encodedCredentials是我的使用者秘密和用户密钥,编码在基数64中。
我想要做的是:
POST /oauth2/token HTTP/1.1
Host: api.twitter.com
User-Agent: My Twitter App v1.0.23
Authorization: Basic eHZ6MWV2RlM0d0VFUFRHRUZQSEJvZzpMOHFxOVBaeVJn
NmllS0dFS2hab2xHQzB2SldMdzhpRUo4OERSZHlPZw==Content-Type: application/x-www- form-urlencoded;charset=UTF-8
Content-Length: 29
Accept-Encoding: gzip
grant_type=client_credentials我不断得到403禁止:{“错误”:{“代码”:170,“消息”:“缺少必需的参数: grant_type",”标签“:”forbidden_missing_parameter“}}
似乎帖子的主体设置不正确,有人知道怎么设置吗?
发布于 2015-01-13 09:50:45
您可以尝试更改POST请求主体/实体的内容类型,如下所示:
.post(Entity.entity("grant_type=client_credentials", MediaType.APPLICATION_FORM_URLENCODED)发布于 2015-01-13 09:31:35
我在PHP中使用过相同的参数,我认为您忽略了所需的参数,比如oauth_signature。
发布于 2015-01-13 10:01:02
因此,从Twitter获得具有使用者密钥和消费者秘密的承载令牌的最终代码如下所示:
private static final String OAUTH_API_ENDPOINT = "https://api.twitter.com/oauth2/token";
private String consumerKey = "your consumer key";
private String consumerSecret = "your consumer secret";
// Constructs the request for requesting a bearer token and returns that
// token as a string
public String requestBearerToken() throws IOException, InterruptedException, ExecutionException {
String encodedCredentials = encodeCredentials();
Client client = ClientBuilder.newClient();
WebTarget target = new WebTargetBuilder(client, OAUTH_API_ENDPOINT).build();
Response postResponse = target
.request(MediaType.APPLICATION_JSON)
.header("Authorization", "Basic " + encodedCredentials + "Content-Type: application/x-www-form-urlencoded;charset=UTF-8")
.post(Entity.entity("grant_type=client_credentials", MediaType.APPLICATION_FORM_URLENCODED));
return postResponse.toString();
}
// Encodes the consumer key and secret to create the basic authorization key
public String encodeCredentials() {
try {
String encodedConsumerKey = URLEncoder.encode(consumerKey, "UTF-8");
String encodedConsumerSecret = URLEncoder.encode(consumerSecret,
"UTF-8");
String fullKey = encodedConsumerKey + ":" + encodedConsumerSecret;
byte[] encodedBytes = Base64.encodeBase64(fullKey.getBytes());
return new String(encodedBytes);
} catch (UnsupportedEncodingException e) {
return new String();
}
}https://stackoverflow.com/questions/27917249
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