我需要一个bash脚本来替换dnsmasq.conf中的整行
默认情况下,行如下:
listen-address=192.168.42.1
dhcp-range=192.168.42.1,192.168.42.253,255.255.255.0,192.168.42.255,24h
dhcp-option=option:router,192.168.42.1我执行:
new_ip=$1
broadcast=$2
base_ip=`echo $new_ip | cut -d"." -f1-3`
sed -i 's/^listen-address.*/listen-address=$new_ip/' /etc/dnsmasq.conf
sed -i 's/^dhcp-range.*/dhcp-range=$base_ip.1,$base_ip.254,255.255.255.0,$broadcast,24h/' /etc/dnsmasq.conf
sed -i 's/^dhcp-option.*/dhcp-option=option:router,$new_ip/' /etc/dnsmasq.conf我将bash称为./test.sh 172.24.239.40 172.24.239.255,并获得以下行:
listen-address=$new_ip
dhcp-range=$base_ip.1,$base_ip.254,255.255.255.0,$broadcast,24h
dhcp-option=option:router,$new_ip是否可以将参数与sed命令行中的文本分离?
发布于 2015-01-08 14:56:43
您可以使用:
sed -i.bak -e "s/^listen-address.*/listen-address=$new_ip/" \
-e "s/^dhcp-range.*/dhcp-range=$base_ip.1,$base_ip.254,255.255.255.0,$broadcast,24h/" \
-e "s/^dhcp-option.*/dhcp-option=option:router,$new_ip/" /etc/dnsmasq.conf即
sed-i.bak保证原始文件的安全和.bak扩展名发布于 2015-01-08 14:57:24
在sed中有变量时,使用双引号而不是单引号:
sed -i "s/^listen-address.*/listen-address=$new_ip/" /etc/dnsmasq.conf
sed -i "s/^dhcp-range.*/dhcp-range=$base_ip.1,$base_ip.254,255.255.255.0,$broadcast,24h/" /etc/dnsmasq.conf
sed -i "s/^dhcp-option.*/dhcp-option=option:router,$new_ip/" /etc/dnsmasq.confhttps://stackoverflow.com/questions/27842943
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