如何将ResultSet转换为JSON对象

Question

我们尝试使用以下代码将ResultSet转换为JSON对象：

var getAllCalelements = {};           // Object
    getAllCalelements['totalamount'] = [];          
    getAllCalelements['totalamount'].push(result.rows.item(i).totalamount);
    getAllCalelements['discount'] = [];          
    getAllCalelements['discount'].push(result.rows.item(i).invoicediscount);
    getAllCalelements['NetAmount'] = [];          
    getAllCalelements['NetAmount'].push(result.rows.item(i).namount);
    getAllCalelements['vat'] = [];          
    getAllCalelements['vat'].push(result.rows.item(i).vat);
    getAllCalelements['GrossAmount'] = [];          
    getAllCalelements['GrossAmount'].push(result.rows.item(i).gamount);
    getAllCalelements['bookOrder'] = [];          
    getAllCalelements['bookOrder'].push(result.rows.item(i).bookorder);

var json = JSON.stringify(getAllCalelements, undefined, 2);

但是，我们有这样的JSON

{
  "totalamount": [19760.22],
  "discount": [ 7],
  "NetAmount": [ 18377],
  "vat": [ 8],
  "GrossAmount": [ 8],
  "bookOrder": [ "ABCANG00110"]
}

而且，我们需要像这样的JSON输出

[
    {
        "totalamount": 19760.22,
        "discount": 7,
        "NetAmount": 18377,
        "vat": 8,
        "GrossAmount": 8,
        "bookOrder": "ABCANG00555"
    }
]    

我已经尝试过了，但是我没有像上面提到的那样获得欲望输出，而是得到了JSON输出。但我们需要上述格式的JSON。请指导我得到上面提到的我的愿望输出，谢谢。

Answer 1

var obj = [];

for (var i = 0; i < result.rows.length; i++){

    var getAllCalelements = {};           // Object
    getAllCalelements['totalamount'] = result.rows.item(i).totalamount ;
    getAllCalelements['discount'] = result.rows.item(i).invoicediscount;
    getAllCalelements['NetAmount'] = result.rows.item(i).namount;
    getAllCalelements['vat'] = result.rows.item(i).vat;
    getAllCalelements['GrossAmount'] = result.rows.item(i).gamount;
    getAllCalelements['bookOrder'] = result.rows.item(i).bookorder;
    obj.push(getAllCalelements);

}

var json = JSON.stringify(obj, undefined, 2); 

Answer 2

试试下面的代码：

var obj = {};
obj = [];

for(var i=0;i<result.rows.item.length;i++)
{
    var getAllCalelements = {};           // Object
    getAllCalelements['totalamount'] = result.rows.item(i).totalamount ;
    getAllCalelements['discount'] = result.rows.item(i).invoicediscount;
    getAllCalelements['NetAmount'] = result.rows.item(i).namount;
    getAllCalelements['vat'] = result.rows.item(i).vat;
    getAllCalelements['GrossAmount'] = result.rows.item(i).gamount;
    getAllCalelements['bookOrder'] = result.rows.item(i).bookorder;

    obj.push(getAllCalelements);
}
var json = JSON.stringify(obj, undefined, 2);  

产出：

[
  {
    "totalamount": "19760.22",
    "discount": "7",
    "NetAmount": "18377",
    "vat": "8",
    "GrossAmount": "8",
    "bookOrder": "ABCANG00110"
  }
]  

如果要通过obj向obj.push(getAllCalelements)添加第二个对象，则输出将低于

[
  {
    "totalamount": "19760.22",
    "discount": "7",
    "NetAmount": "18377",
    "vat": "8",
    "GrossAmount": "8",
    "bookOrder": "ABCANG00110"
  },
  {
    "totalamount": "19760.22",
    "discount": "7",
    "NetAmount": "18377",
    "vat": "8",
    "GrossAmount": "8",
    "bookOrder": "ABCANG00110"
  }
]

Answer 3

@aschattney临时编写了您的答案，并使用Object.keys()使其动态化，还将其封装在一个函数中，因此您可以传递resultSet，即在本例中，sqlResultSet并返回有效的JSON。

  function returnJsonFromSqlResultSet(sqlResultSet) {

    var objArr = [];

    if (sqlResultSet.rows.length > 0) {

      var objKeys = Object.keys(sqlResultSet.rows.item(0)); //sample the keys from first element

      for (var i = 0; i < sqlResultSet.rows.length; i++) {

        var jsonObj = {}; // Object

        for (var j = 0; j < objKeys.length; j++) {
          jsonObj[objKeys[j]] = sqlResultSet.rows.item(i)[objKeys[j]];
        }

        objArr.push(jsonObj);

      }

      var json = JSON.stringify(objArr, undefined, 2);
      return json;

    }
}

谢谢!