XmlPullParser名称预期异常

Question

我尝试使用以下代码读取我的应用程序创建的XML文件：

XmlPullParser xpp = factory.newPullParser();
xpp.setInput(new StringReader(data));
int eventType = xpp.getEventType();

while(eventType != XmlPullParser.END_DOCUMENT)
{
    switch(eventType)
    {
        case XmlPullParser.START_TAG:
        {
            String tagName = xpp.getName();
            // do something
            break;
        }
        case XmlPullParser.TEXT:
        {
            // get text...
            break;
        }
        case XmlPullParser.END_TAG:
        {
            // do something
            break;
        }
    }

    eventType = xpp.next();
}

但是一开始，当eventType是START_DOCUMENT时，next()函数会抛出异常: org.xmlpull.v1.XmlPullParserException: name (position:START_TAG @2:2在java.io.StringReader@41084cc8中)

你知道为什么吗？

以下是我的XML文件：

<?xml version='1.0' encoding='UTF-8' standalone='yes' ?>
<0>
  <createTime>1419453655800</createTime>
  <editTime>1419453655800</editTime>
  <color>2</color>
  <text>ooooo</text>
</0>
<1>
  <createTime>1419453586197</createTime>
  <editTime>1419453605679</editTime>
  <color>1</color>
  <text>uuuuuuuuu</text>
</1>
<2>
  <createTime>1419453358866</createTime>
  <editTime>1419453597124</editTime>
  <color>2</color>
  <text>yyyyyyyyyy</text>
</2>

Answer 1

为XML well-formed 提供一个根元素，并使元素名以字母而不是数字开头：

<?xml version='1.0' encoding='UTF-8' standalone='yes' ?>
<top>
  <e0>
    <createTime>1419453655800</createTime>
    <editTime>1419453655800</editTime>
    <color>2</color>
    <text>ooooo</text>
  </e0>
  <e1>
    <createTime>1419453586197</createTime>
    <editTime>1419453605679</editTime>
    <color>1</color>
    <text>uuuuuuuuu</text>
  </e1>
  <e2>
    <createTime>1419453358866</createTime>
    <editTime>1419453597124</editTime>
    <color>2</color>
    <text>yyyyyyyyyy</text>
  </e2>
</top>