如何创建从星期三到星期五到星期五上午10点更改的七天数组

Question

这就是：

如果本周星期五少于10:00，则创建包含前一周的星期六的数组，则在本周的星期日、星期一、星期二、星期三和星期五进行数组。

如果现在在本周星期五超过10:00，则用包含本星期的星期六的另一个数组替换之前的数组，然后是下一周的星期日、星期一、星期二和星期五。

我不能用脚本来表达这种情况的逻辑。

谢谢

在读了很多很多帖子之后，我来到这个不起作用的地方。

$current_time = strtotime('now');
$week_start_day = "friday";
$start_time = "10:00";

if ($current_time <= strtotime('$week_start_day this week $start_time')) {
    $day_1 = date('d/m/Y', strtotime('previous week friday', strtotime(date('d-m-Y'))));
    $day_2 = date('d/m/Y', strtotime('previous week saturday ', strtotime(date('d-m-Y'))));
    $day_3 = date('d/m/Y', strtotime('previous week sunday  ', strtotime(date('d-m-Y'))));
    $day_4 = date('d/m/Y', strtotime('previous week monday', strtotime(date('d-m-Y'))));
    $day_5 = date('d/m/Y', strtotime('previous week tuesday', strtotime(date('d-m-Y'))));
    $day_6 = date('d/m/Y', strtotime('this week wednesday  ', strtotime(date('d-m-Y'))));   
    $day_7 = date('d/m/Y', strtotime('this week thursday ', strtotime(date('d-m-Y')))); 

} 
else{

    $day_1 = date('d/m/Y', strtotime('this week saturday  ', strtotime(date('d-m-Y'))));
    $day_2 = date('d/m/Y', strtotime('this week sunday', strtotime(date('d-m-Y'))));
    $day_3 = date('d/m/Y', strtotime('this week monday', strtotime(date('d-m-Y'))));
    $day_4 = date('d/m/Y', strtotime('this week tuesday  ', strtotime(date('d-m-Y')))); 
    $day_5 = date('d/m/Y', strtotime('this week wednesday ', strtotime(date('d-m-Y'))));    
    $day_6 = date('d/m/Y', strtotime('this week thursday ', strtotime(date('d-m-Y'))));
    $day_7 = date('d/m/Y', strtotime('this week friday ', strtotime(date('d-m-Y'))));
}


echo "
    $day_1 <br> 
    $day_2 <br>
    $day_3 <br>
    $day_4 <br> 
    $day_5 <br>
    $day_6 <br> 
    $day_7 <br>     
    ";

Answer 1

如果我对你的理解是正确的，这就是你想要的，没有很好的测试，所以可能会有错误，但这就是想法。

$fri=strtotime(" Friday this week + 4 hours ");// 10:00 GMT 
$now=time();

$week=array();

if($now<=$fri)
{
    $day = "last Saturday";
}
else
{
    $day = "next Saturday";
}

for($i=0;$i<7;$i++)
{
    $week[] = date("d/m/Y", strtotime($day." +".$i." day"));
}

foreach($week as $day)
{
    echo $day;
}