从UITouch获得UIPanGestureRecognizer

Question

是否可以通过UITouch获得一个UIPanGestureRecognizer对象？我该怎么做？

Answer 1

作为苹果公司的文件说，没有一个属性来获取UIGestureRecognizer对象中的touch。但是您可以子类UIGestureRecognizer类，以便重写touchesBegan:withEvent:、touchesMoved:withEvent:、touchesEnded:withEvent:等，从而检索UITouch对象。

如果可以有用，也可以查看locationOfTouch:inView:。

干杯!

Answer 2

我解决了这个问题：

PanGestureRecognizer.h文件

#import <UIKit/UIKit.h>
#import <UIKit/UIGestureRecognizerSubclass.h>

@interface PanGestureRecognizer : UIPanGestureRecognizer {

}

- (void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event;

@end

@protocol PanGestureRecognizer <UIGestureRecognizerDelegate>

- (void) panGestureRecognizer:(UIPanGestureRecognizer *)gr movedWithTouches:(NSSet*)touches andEvent:(UIEvent *)event;


@end

PanGestureRecognizer.m文件

#import "PanGestureRecognizer.h"


@implementation PanGestureRecognizer

- (void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event {

    [super touchesMoved:touches withEvent:event];

    if ([self.delegate respondsToSelector:@selector(panGestureRecognizer:movedWithTouches:andEvent:)]) {
        [(id)self.delegate panGestureRecognizer:self movedWithTouches:touches andEvent:event];
    }

}

@end

GestureView.m文件

- (void)awakeFromNib {
        PanGestureRecognizer *panRecognizer = [[PanGestureRecognizer alloc] initWithTarget:self action:@selector(panRecognition:)];
        panRecognizer.maximumNumberOfTouches = 1;
        [panRecognizer setDelaysTouchesBegan:NO];
        [panRecognizer setDelaysTouchesEnded:NO];
        [panRecognizer setCancelsTouchesInView:NO];
        panRecognizer.delegate = self;
        [self.keyboardLayoutView addGestureRecognizer:panRecognizer];
}

- (void)panGestureRecognizer:(UIPanGestureRecognizer *)panRecognizer movedWithTouches:(NSSet*)touches andEvent:(UIEvent *)event{

}