我希望为不同类型的对象构建数据结构,这些对象具有不同的访问相同类型参数的方法。例如,
圆圈对象的x-coord前有一个组代码作为10,而行对象的x-coord前有一个标头,为30。而且,对象并不总是具有相同的参数。
因此,从任何对象提取所有必要参数的泛型函数如下所示:
(define (build-struct lst)
(if (empty? lst)
empty
(begin (make-entity (find-params (string=? (car (car lst)))))
(build-struct (cdr lst)))))
;function to build structs from a list of lists (that contain an object)
(define-struct entity (name x-coord y-coord layer-name [num-vertices #:auto] [radius #:auto] [start-angle #:auto] [end-angle #:auto])
#:auto-value empty)
;data struct to store object param values
(define (find-circle-param lst parameter)
(let ((kw (string-upcase parameter)))
(if (empty? lst)
'() ;put error message here
(cond ((and (string=? kw "X-COORD") (= (car lst) "10"))
(cadr lst))
((and (string=? kw "Y-COORD") (= (car lst) "20"))
(cadr lst))
((and (string=? kw "LAYER-NAME") (= (car lst) "8"))
(cadr lst))
((and (string=? kw "RADIUS") (= (car lst) "40"))
(cadr lst))
(else #f)))))
(define (find-line-param lst parameter)
(let ((kw (string-upcase parameter)))
(if (empty? lst)
'() ;put error message here
(cond ((and (string=? kw "X-COORD-START") (= (car lst) "10"))
(cadr lst))
((and (string=? kw "Y-COORD-START") (= (car lst) "20"))
(cadr lst))
((and (string=? kw "X-COORD-END") (= (car lst) "11"))
(cadr lst))
((and (string=? kw "Y-COORD-END") (= (car lst) "21"))
(cadr lst))
((and (string=? kw "LAYER-NAME") (= (car lst) "8"))
(cadr lst))
(else #f)))))
;functions to find parameter value depending on object type我只想创建一个函数来寻找参数。
发布于 2014-12-08 12:55:09
结构可以有一个超级类型。如果您有几个具有共同属性的结构,请考虑给它们一个普通的超级类型。下面是一个示例:
#lang racket
(struct shape (x y) #:transparent) ; all shapes has x and y coordinates
(struct circle shape (radius) #:transparent) ; a circle has besides the center also a radius
(struct line shape (x-end y-end) #:transparent) ; a line has besides its start point also end coords
(define c (circle 1 2 3))
(define l (line 4 5 6 7))
(define (position a-shape)
(match a-shape
[(shape x y) (list "Position:" x y)]
[_ (error 'position "expected a shape, got ~a" a-shape)]))
(position c)
(position l)请注意,位置的定义可以同时找到圆和线的位置,而不需要在位置定义中明确提到圆和线。
https://stackoverflow.com/questions/27352550
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