在NLTK3中遍历零块的问题

Question

嗨，我在NLTK 3中尝试这段代码：-不知何故，我设法修复了行-6来使用NLTK的第3版。但是for循环仍然没有返回任何内容。

import nltk
sample = """ some random text content with names and countries etc"""     
sentences = nltk.sent_tokenize(sample)
tokenized_sentences = [nltk.word_tokenize(sentence) for sentence in sentences]
tagged_sentences = [nltk.pos_tag(sentence) for sentence in tokenized_sentences]
chunked_sentences=nltk.chunk.ne_chunk_sents(tagged_sentences) #Managed to fix this to work with version_3

for i in chunked_sentences:
    if hasattr(i,'label'):
        if i.label()=='NE':
            print i

此外，如果我尝试调试，我会看到以下输出：

for i in chunked_sentences:
    if hasattr(i,'label') and i.label:
        print i.label
S
S
S
S
S
S
S
S

那我怎么查"NE“呢？NLTK-3有什么问题，我真的无法理解out.Pls的帮助

Answer 1

看来你在重复句子。我假设您想要迭代句子中包含的各个节点。

它应该是这样的：

for sentence in chunked_sentences:
    for token in sentence: 
       if hasattr(token,'label') and token.label() == 'NE':
           print token

编辑:为了将来的参考，让我意识到你在重复句子这个事实的是，一个句子的根节点通常被标记为'S‘。