我想用jquery插件Fancytree显示一个数据结构。在Google中进行长时间搜索之后,将数据结构存储在数据库中的最佳方法似乎是嵌套的Set模型(在这里的Stackoverflow中描述)。然而,要显示这种结构的相关嵌套JSON是相当困难的,我无法做到。
这包括转换以下MySQL表:
( category_id )\x{e76f}\x{e76f}=
\x{e76f}\x{e76f}电子产品1,000,000
\x{e76f}\x{e76f}2电视
\x{e76f}\x{e76f}管状
\x{e76f}5-等离子体-7-8-2
\x{e76f}\x{e76f}6-便携式电子产品- 10 - 19 -1
\x{e76f}\x{e76f} MP3球员
#^#^#^=#^#^#.
\x{e76f}\x{e76f} CD播放机
\x{e76f}\x{e76f}2双向无线电台
到这个JSON中:
[{"key": "1", "title": "ELECTRONICS", "expanded": true, "children": [
{"key": "2", "title": "TELEVISION", "expanded": true, "children": [
{"key": "3", "title": "TUBE"},
{"key": "4", "title": "LCD"},
{"key": "5", "title": "PLASMA"}
]},
{"key": "6", "title": "PORTABLE ELECTRONICS", "expanded": true, "children": [
{"key": "7", "title": "MP3 PLAYERS", "expanded": true, "children": [{"key": "8", "title": "FLASH"}]},
{"key": "9", "title": "CD PLAYERS"},
{"key": "10", "title": "2 WAY RADIOS"}
]}
]}]我想知道它是否存在将MySQL数据转换为分层嵌套JSON的简单方法?谢谢!
发布于 2014-11-30 07:38:23
最后,通过一点一点地使JSON工作,我设法使我的树工作起来。我不认为它是适当的,因为它不是由对象和数组组成的,但这似乎很好。
<?php
if (!isset($DB_connection)) { require_once('../config/_db_connect.php'); }
$result = $DB_connection->prepare("SELECT node.category_id, node.name,
(COUNT(parent.name) - 1) AS depth FROM nested_category AS node,
nested_category AS parent WHERE node.lft BETWEEN parent.lft
AND parent.rgt GROUP BY node.name ORDER BY node.lft;");
$result->execute();
$i = 0;
$nb_open = 0;
$current_level = '';
echo "[{";
while( $line = $result->fetch(PDO::FETCH_OBJ) )
{
if ($current_level == '') { $current_level = $line->depth; }
if ($current_level == $line->depth) { if ($i > 0) { echo " }, {"; } }
elseif ($current_level < $line->depth) {
echo ', "children": [ { ';
$nb_open = $nb_open + 1;
}
elseif ($current_level > $line->depth) {
$nb_to_close = $current_level - $line->depth;
for ($j = 1; $j <= $nb_to_close; $j++) {
$nb_open = $nb_open - 1;
echo " }]";
}
echo "}, {";
}
echo ' "title": "' . $line->name . '", "key": "' .
$line->category_id . '", "expanded": true';
$current_level = $line->depth;
$i++;
}
if ($nb_open>0) { for ($i = 1; $i <= $nb_open; $i++) { echo "}]"; } }
echo "}]";
?>https://stackoverflow.com/questions/27201129
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