Shell脚本编写参数

Question

for (( i=1; i<=$#; i++ ))
do
    echo "$($i)"    <---this is not correct, how should i fix that?
done

我想打印所有参数。

Answer 1

for arg; do
    echo "$arg";
done

或

for ((i=0; i<=${#@}; i++ )); do
    echo "${!i}"
done

或

for arg in "$@"; do
    echo "$arg";
done