Java运行程序

Question

这是一个非常简单的程序。我已经创建了一个新的类，我将定义一个新的方法来回忆一个新类中的下一步。

public class MyClass {

    public static void main(String[] args) {
        int number = 1;
        public void showSomething(){
            System.out.println("This is my method "+number+" created by me.");
        }

    }
}

但是，当我运行这个程序时，我遇到了一个错误：

Exception in thread "main" java.lang.Error: Unresolved compilation problems: 
    Syntax error on token(s), misplaced construct(s)
    Syntax error on token "void", @ expected

Answer 1

错误是因为您在这里的另一个方法-- main()中声明一个方法。

改变这一点：

public static void main(String[] args) {
    int number = 1;
    public void showSomething(){
        System.out.println("This is my method "+number+" created by me.");
    }

}

至

public static void main(String[] args) {
    int number = 1;
    showSomething(); // call the method showSomething()
}
public static void showSomething(){
    System.out.println("This is my method "+number+" created by me.");
}

另外，showSomething()应该声明为static，因为main()是static。只能从另一个static methods调用static method。

Answer 2

不能将方法声明为方法。

这样做吧：

public class MyClass {

  public static void main(String[] args) {
    int number = 1;
    showSomething(number);
  }

  public static void showSomething(int number){
    System.out.println("This is my method "+number+" created by me.");
  }
}

Answer 3

public class MyClass {

public static void main(String[] args) {
    new MyClass().showSomething();
}

public void showSomething(){
        int number = 1;
        System.out.println("This is my method "+number+" created by me.");
}

}