Python glutCreateWindow错误“错误类型”

Question

我正在尝试在python中创建一个具有create的窗口，并有以下代码：

glutInit()
    glutInitWindowSize(windowWidth, windowHeight)
    glutInitWindowPosition(int(centreX - windowWidth/2), int(centreY - windowHeight/2))
    glutCreateWindow("MyWindow")
    glutInitDisplayMode(GLUT_SINGLE | GLUT_RGB | GLUT_DEPTH)
    glutDisplayFunc(displayFun)
    glutIdleFunc(animateFun)
    glutKeyboardFunc(keyboardFun)
    glutPassiveMotionFunc(mouseFun)

    glutReshapeFunc(reshapeFun)
    initFun()
    #loadTextures()
    glutMainLoop()

我在“glutCreateWindow”行中看到一个错误，它是这样写的：

Traceback (most recent call last):
  File "F:\MyProject\main.py", line 301, in <module>
    glutCreateWindow("MyWindow")
  File "C:\Python34\lib\site-packages\OpenGL\GLUT\special.py", line 73, in glutCreateWindow
    return __glutCreateWindowWithExit(title, _exitfunc)
ctypes.ArgumentError: argument 1: <class 'TypeError'>: wrong type

此函数的文档指定

int glutCreateWindow(char *name);

Answer 1

我刚刚遇到了同样的问题，发现了这篇博客文章：

http://codeyarns.com/2012/04/27/pyopengl-glut-ctypes-error/

基本上，您需要指定正在传递字节数据，而不是使用b'Window Title'传递字符串。

Answer 2

除了在字符串之前添加一个b之外：

b"MyWindow"

您还可以使用以下方法将字符串转换为ascii字节：

bytes("MyWindow","ascii")

有关更多细节，您可以参考以下链接：

PyOpenGL过剩类型错误

Python 3阅读器

Answer 3

def glutCreateWindow(title):
    """Create window with given title

    This is the Win32-specific version that handles
    registration of an exit-function handler 
    """
    return __glutCreateWindowWithExit(title.encode(), _exitfunc)

为了最终解决这个问题，您需要更改lib/site-packages/OpenGL/GLUT/special.py文件的内容，如这样或这样：

def glutCreateWindow(title):
    """Create window with given title

    This is the Win32-specific version that handles
    registration of an exit-function handler 
    """
    return __glutCreateWindowWithExit(bytes(title,"ascii"), _exitfunc)