MVC模型转换错误

Question

如何设置不同的模式？

  List<ORDER_DETAILSMetadata> result = db.ORDER_DETAILS.Where(p => p.Order_Number == id).ToList();

错误6不能隐式地将类型“System.Collections.Generic.List<Mvc5.Models.ORDER_DETAILS>”转换为“System.Collections.Generic.List<Mvc5.Models.ORDER_DETAILSMetadata>”

ORDER_DETAILSMetadata

MetadataType(typeof(ORDER_DETAILSMetadata))]
public partial class ORDER_DETAILS
{
    // Note this class has nothing in it.  It's just here to add the class-level attribute.
}

public class ORDER_DETAILSMetadata
{
    public int Order_Details_ID { get; set; }
    public Nullable<int> Order_Number { get; set; }
    public Nullable<short> Sequence_Number { get; set; }
    public string Item_Num { get; set; }
    public Nullable<short> Order_Quantity { get; set; }
    public Nullable<short> Ship_Quantity { get; set; }

}

ORDER_DETAILS.cs

 public partial class ORDER_DETAILS
{
    public int Order_Details_ID { get; set; }
    public Nullable<int> Order_Number { get; set; }
    public Nullable<short> Sequence_Number { get; set; }
    public string Item_Num { get; set; }
    public Nullable<short> Order_Quantity { get; set; }
    public Nullable<short> Ship_Quantity { get; set; }
}

Answer 1

据我所知，你可以这样做：

List<ORDER_DETAILSMetadata> result = db.ORDER_DETAILS.
                                     Where(p => p.Order_Number == id).
                                     Select(x => new ORDER_DETAILSMetadata 
                                           {
                                              Order_Details_ID = x.Order_Details_ID,
                                              Order_Number = x.Order_Number,
                                              Sequence_Number = x.Sequence_Number,
                                              Item_Num = x.Item_Num,
                                              Order_Quantity = x.Order_Quantity,
                                              Ship_Quantity = x.Ship_Quantity

                                           }).ToList();

如果您只想将一种类型的模型转换为另一种类型，您可以这样做：

List<target> targetList = new List<target>(originalList.Cast<target>());

您可以查看有关Cast()和OfType() 这里的详细信息。当您有不同的计数和字段类型时，请使用第一种方法。