我似乎不能让这段代码起作用。它一直给我错误“对不起:查询失败”。有到数据库的连接,因为如果我输入了错误的密码,它将给出"mysql连接失败“错误。表宠物已经创建并填充了数据。拜托,我需要帮助
<?php
$conn = mysql_connect ("localhost", "vistor", "visitor", "test")
or die ("sorry: Mysql connection failed");
$query = "select * from pet";
$result = mysql_query ($query,$conn)
or die ("sorry: query failed");
while($row = mysql_fetch_array($result)) {
echo $row['code'], " ", $row['name'];
echo "<br>";
}
mysql_close($conn);
?>Donny给了我下面的代码,我添加了一些css,使它看起来像一个表,但我怀疑我的编码错误,因为我得到了错误。谢谢
<html>
<head>
<title> php test script - hope this works </title>
</head>
<body>
<h1>php & mysql connection</h1>
<hr>
<?php
$db_host = "localhost";
$db_username = "vistor";
$db_pass = "visitor";
$db_name = "test";
$db = new PDO('mysql:host='.$db_host.';dbname='.$db_name,$db_username,$db_pass);
$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_WARNING);
$query = $db->query('SELECT * FROM pet');
echo "<table border = '2'>"
<tr>
<th>id</th>
<th>name</th>
</tr>
while ($row = $query->fetch())
{
echo "<tr>";
echo "<td>" . $row['id'] ."</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['price'] . "</td>";
echo "</tr>;
}
echo "</table>";
?>
</body>
</html>发布于 2014-11-19 20:36:43
您应该学习如何在准备好的PDO语句中编写代码。因为MySQL将被废弃,用MySQL编写它可能会给您的注射带来麻烦。这就是如何在准备好的PDO语句中编写这段代码。您可以用MySQLI编写它,但唯一的问题是,除了MySQL之外,您无法在任何其他数据库中使用您的代码。使用PDO,您可以使用您的代码与任何数据库,如SQL,Access等。
<?php
$db_host = "localhost";
$db_username = "visitor";
$db_pass = "visitor";
$db_name = "test";
$db = new PDO('mysql:host='.$db_host.';dbname='.$db_name,$db_username,$db_pass);
$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_WARNING);
$query = $db->query('SELECT * FROM pet');
while ($row = $query->fetch()) {
echo $row['code'], " ", $row['name'];
}
?>发布于 2014-11-19 20:07:41
您能提供数据库连接和查询的完整代码吗?
请记住,mysql_*函数在PHP中已被废弃,如果您仍然想使用它们,您应该能够这样做:
<?php
//create connection to MySQL
$link = mysql_connect('mysql_host', 'mysql_user', 'mysql_password');
//select database
mysql_select_db('mysql_dbname', $link);
//create and execute query
$sql = 'SELECT foo FROM bar WHERE id = 42';
$result = mysql_query($sql, $link);
?>https://stackoverflow.com/questions/27025926
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