请看下面的示例:
public void start(){
//...
locationManager.requestLocationUpdates(LocationManager.GPS_PROVIDER, TEN_SECONDS, TEN_METERS, this);
}
@Override
public void onLocationChanged(Location location) {
if(location.distanceTo(_lastLocation) > TEN_KM_IN_METERS){
actionA(location);
_lastLocation = location;
} else {
actionB(location);
}
}Location#distanceTo(l)的实现相当复杂,而且需要大量的CPU.所以我不想在每次更新位置的时候都打电话给这个行动。
问题:这是避免不必要的 Location#distanceTo(l) 调用的正确方法吗?
到目前为止我尝试过的。根据Wiki -十进制度的说法,我是这样做的:
private boolean closeTogether(Location a, Location b) {
double changeLat = Math.abs(a.getLatitude() - b.getLatitude());
final float myNaiveMax = 0.005;
if (changeLat > myNaiveMax) {
return false;
}
double changeLon = Math.abs(a.getLongitude() - b.getLongitude());
if (changeLon > myNaiveMax) {
return false;
}
return true;
}
@Override
public void onLocationChanged(Location location) {
if(!closeTogether(location, _lastLocation) && location.distanceTo(_lastLocation) > TEN_KM_IN_METERS){
actionA(location);
_lastLocation = location;
} else {
actionB(location);
}
}发布于 2014-11-14 15:51:34
我发现Haversine公式对此非常有用。适用于我的送货跟踪应用程序。这是我如何计算两点之间的距离。应该让你开始:)
/**
* getDistanceBetweenTwoPoints
* @param p1 - First point
* @param p2 - Second point
* @return distance between the two specified points (as the crow flys)
*/
public static double getDistanceBetweenTwoPoints(PointF p1, PointF p2) {
double R = 6371000; // Earth radius
double dLat = Math.toRadians(p2.x - p1.x);
double dLon = Math.toRadians(p2.y - p1.y);
double lat1 = Math.toRadians(p1.x);
double lat2 = Math.toRadians(p2.x);
double a = Math.sin(dLat / 2) * Math.sin(dLat / 2) + Math.sin(dLon / 2)
* Math.sin(dLon / 2) * Math.cos(lat1) * Math.cos(lat2);
double c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1 - a));
double d = R * c;
return d;
}编辑和另一个
public static PointF calculateDerivedPosition(PointF point,
double range, double bearing)
{
double EarthRadius = 6371000; // m
double latA = Math.toRadians(point.x);
double lonA = Math.toRadians(point.y);
double angularDistance = range / EarthRadius;
double trueCourse = Math.toRadians(bearing);
double lat = Math.asin(Math.sin(latA) * Math.cos(angularDistance) +
Math.cos(latA) * Math.sin(angularDistance) * Math.cos(trueCourse));
double dlon = Math.atan2(Math.sin(trueCourse) * Math.sin(angularDistance) * Math.cos(latA),
Math.cos(angularDistance) - Math.sin(latA) * Math.sin(lat));
double lon = ((lonA + dlon + Math.PI) % (Math.PI * 2)) - Math.PI;
lat = Math.toDegrees(lat);
lon = Math.toDegrees(lon);
PointF newPoint = new PointF((float) lat, (float) lon);
return newPoint;
}https://stackoverflow.com/questions/26933694
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