我必须在一个图中绘制两个不同的dataSets。
数据集-1
String[] xAxisOne = new String[] {
"0", "1", "2", "3", "4", "5", "6"
};
float[] dataInput = {
1f, 2f, 3f, 4f, 5f, 6f, 7f
};数据集-2
String[] xAxisTwo = new String[] {
"0", "2", "4", "5", "6", "8", "9"
};
float[] dataIn = {
3f, 4f, 5f, 6f, 7f, 8f, 9f
};在上述数据中,DataSet-1是创建图形的引用。DataSet-2必须用不同的X值{xAxisTwo}以相同的方式绘制.
在现有实现中,绘制前6个值{dataInput},并参照xAxisOne绘制接下来的6个值{dataIn},如何根据需要绘制。
发布于 2015-08-07 02:21:06
您可以使用LineChart和统一xAxis并忽略每个数据集的"null“点来完成此操作。见下面的代码:
//float[] dataInput = {
// 1f, 2f, 3f, 4f, 5f, 6f, 7f
//};
//values for datainput Dataset1 at your axisone positions
ArrayList<Entry> dataset1 = new ArrayList<Entry>();
dataset1.add(new Entry(1f, 0));
dataset1.add(new Entry(2f, 1));
dataset1.add(new Entry(3f, 2));
dataset1.add(new Entry(4f, 3));
dataset1.add(new Entry(5f, 4));
dataset1.add(new Entry(6f, 5));
dataset1.add(new Entry(7f, 6));
//float[] dataIn = {
// 3f, 4f, 5f, 6f, 7f, 8f, 9f
//};
//values for datainput Dataset2 at your axisone positions
ArrayList<Entry> dataset2 = new ArrayList<Entry>();
dataset2.add(new Entry(3f, 0));
dataset2.add(new Entry(4f, 2));
dataset2.add(new Entry(5f, 4));
dataset2.add(new Entry(6f, 5));
dataset2.add(new Entry(7f, 6));
dataset2.add(new Entry(8f, 7));
dataset2.add(new Entry(9f, 8));
//String[] xAxisOne = new String[] {
// "0", "1", "2", "3", "4", "5", "6"
//};
///String[] xAxisTwo = new String[] {
/// "0", "2", "4", "5", "6", "8", "9"
///};
// Union from xAxisOne and xAxisTwo
String[] xAxis = new String[] {"0", "1", "2", "3", "4", "5", "6", "8", "9"};
ArrayList<LineDataSet> lines = new ArrayList<LineDataSet> ();
LineDataSet lDataSet1 = new LineDataSet(dataset1, "DataSet1");
lDataSet1.setColor(Color.RED);
lDataSet1.setCircleColor(Color.RED);
lines.add(lDataSet1);
lines.add(new LineDataSet(dataset2, "DataSet2"));
LineChart chart = (LineChart) getView().findViewById(R.id.chart);
chart.setData(new LineData(xAxis, lines));最终结果将是:

看起来dataset1的红线比蓝线多出两个点。如果dataset1只有这两点(位置1和3),如下所示:
ArrayList<Entry> dataset1 = new ArrayList<Entry>();
dataset1.add(new Entry(2f, 1));
dataset1.add(new Entry(4f, 3));其结果是:

发布于 2021-07-22 04:38:41
这需要从第3版开始更新:
对于多行,需要多个数据集。假设您已经创建了两个数据集。
LineDataSet dataSetReported = new LineDataSet(entriesReported, "Reported");
LineDataSet dataSetCalculated = new LineDataSet(entriesCalculated, "Calculated");您需要一个ILINEDATASET列表来容纳所创建的两个数据集。只需创建一个列表并添加数据集。
List<ILineDataSet> lines = new ArrayList<ILineDataSet>();
lines.add(dataSetReported);
lines.add(dataSetCalculated);在图表上显示为:
LineData data = new LineData(lines);
chart.setData(data);
chart.invalidate();有关原始作者的文档,请参阅这里。
发布于 2016-08-23 10:46:03
可以使用此行图传递多个数据集
LineChart lineChart1 = (LineChart) findViewById(R.id.chart1);
ArrayList<Entry> entries = new ArrayList<>();
entries.add(new Entry(4f, 0));
entries.add(new Entry(8f, 1));
entries.add(new Entry(6f, 2));
entries.add(new Entry(10f, 3));
entries.add(new Entry(18f, 4));
entries.add(new Entry(9f, 5));
ArrayList<Entry> entry = new ArrayList<>();
entry.add(new Entry(3f, 0));
entry.add(new Entry(10f, 1));
entry.add(new Entry(4f, 2));
entry.add(new Entry(14f, 3));
entry.add(new Entry(12f, 4));
entry.add(new Entry(5f, 5));
ArrayList<LineDataSet> lines = new ArrayList<LineDataSet> ();
String[] xAxis = new String[] {"1", "2", "3", "4", "5","6"};
LineDataSet lDataSet1 = new LineDataSet(entries, "DataSet1");
lDataSet1.setDrawFilled(true);
lines.add(lDataSet1);
LineDataSet lDataSet2 = new LineDataSet(entry, "DataSet2");
lDataSet2.setDrawFilled(true);
lines.add(lDataSet2);
lineChart1.setData(new LineData(xAxis, lines));
lineChart1.animateY(5000);
}https://stackoverflow.com/questions/26873445
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