我需要将一个数值转换成罗马数字,我遇到了一些麻烦。当我测试我的代码并且用户输入一个数字时,代码会将它转换成一个罗马数字,但是我无法获得提示之后再次出现;在一个不正确的整数放置之后,它会很好地重新提示,而不是在一个正确的整数之后。我不知道如何使用户能够继续转换值,直到他们选择-1退出。下面是我到目前为止想出的。
import java.util.Scanner;
public class arabicToRoman {
static String a = "";
public static void main (String[] args){
Scanner input = new Scanner(System.in);
System.out.println("Enter a number between 1 and 3999 (-1 to quit): ");
while (!input.hasNext("-1")) {
String a = input.next();
try {
Integer number = Integer.parseInt(a);
if ((number <= 3999) && (number > 0)) {
System.out.println(arabicToRoman(number));
} else if (number > 3999) {
System.out.println("Error: number must be between 1 and 3999");
} else if (number == 0) {
System.out.println("Error: The Romans did not have a way to represent negative numbers or zero.");
} else {
System.out.println("Error: The Romans did not have a way to represent negative numbers or zero.");
}
} catch (NumberFormatException e) {
System.out.println("You did not enter a number!");
}
}
}
public static String arabicToRoman(int arabic) {
while (arabic >= 1000){
a += "M";
arabic -= 1000;
}
while (arabic >= 900){
a += "CM";
arabic -= 900;
}
while (arabic >= 500){
a += "D";
arabic -= 500;
}
while (arabic >= 400){
a += "CD";
arabic -= 400;
}
while (arabic >= 100){
a += "C";
arabic -= 100;
}
while (arabic >= 90){
a += "XC";
arabic -= 90;
}
while (arabic >= 50){
a += "L";
arabic -= 50;
}
while (arabic >= 40){
a += "XL";
arabic -= 40;
}
while (arabic >= 10){
a += "X";
arabic -= 10;
}
while (arabic >= 9){
a += "IX";
arabic -= 10;
}
while (arabic >= 5){
a += "V";
arabic -= 5;
}
while (arabic >= 4){
a += "IV";
arabic -= 4;
}
while (arabic >= 1){
a += "I";
arabic -= 1;
}
return a;
}
}输入输入后,它似乎显示了结果,但之后没有提示,用户可以输入其他内容并读取它;如果是另一个数字,则结果将添加到前面的结果中。
发布于 2014-11-09 08:50:41
您的代码无法正常工作,因为满足return条件时调用了((number <= 3999) && (number > 0))语句。此return终止循环。
相反,您可能想调用方法arabicToRoman(int arabic),只需打印出结果。
我还会考虑重组您的代码,使其在sentinel value循环条件下使用while,并编辑代码,以便在给出非数字答案时它不会崩溃。现在编写代码时,这样做将生成一个java.util.InputMismatchException。
Scanner input = new Scanner(System.in);
System.out.println("Enter a number between 1 and 3999 (-1 to quit):");
while (!input.hasNext("-1")) {
String a = input.next(); // gets the next item from the Scanner
try {
Integer number = Integer.parseInt(a); // tries to 'cast' the String to an Integer
if ((number <= 3999) && (number > 0)) {
System.out.println(arabicToRoman(number)); // prints out the result
} else if (number > 3999) {
System.out.println("Error: number must be between 1 and 3999");
} else if (number == 0) {
System.out.println("Error: The Romans did not have a way to represent negative numbers or zero.");
} else {
System.out.println("Error: The Romans did not have a way to represent negative numbers or zero.");
}
} catch (NumberFormatException e) {
System.out.println("You did not enter a number!");
}
}编辑:修复连接问题
所编写的程序正在将结果存储在一个state variable中,该state variable通过对该结果的调用而持久化。这就是为什么每次调用该方法时,它都会打印附加到前一个结果的当前结果。您希望编辑代码以不将a存储为状态变量,并返回arabicToRoman(int arabic)方法而不更改现有数据。在方法中声明变量将允许在方法终止时将其释放。
为了解决这个问题:
首先,在类中的方法之外删除这一行:
static String a = "";然后,编辑您的arabicToRoman(int arabic)方法如下所示:
public static String arabicToRoman(int arabic) {
String a = ""; // note this String declaration at the start of the method
while (arabic >= 1000) {
a += "M";
arabic -= 1000;
}
while (arabic >= 900) {
a += "CM";
arabic -= 900;
}
while (arabic >= 500) {
a += "D";
arabic -= 500;
}
while (arabic >= 400) {
a += "CD";
arabic -= 400;
}
while (arabic >= 100) {
a += "C";
arabic -= 100;
}
while (arabic >= 90) {
a += "XC";
arabic -= 90;
}
while (arabic >= 50) {
a += "L";
arabic -= 50;
}
while (arabic >= 40) {
a += "XL";
arabic -= 40;
}
while (arabic >= 10) {
a += "X";
arabic -= 10;
}
while (arabic >= 9) {
a += "IX";
arabic -= 10;
}
while (arabic >= 5) {
a += "V";
arabic -= 5;
}
while (arabic >= 4) {
a += "IV";
arabic -= 4;
}
while (arabic >= 1) {
a += "I";
arabic -= 1;
}
return a;
}我再次测试这一点,并可以确认它产生了正确的行为,正如您所描述的。
为了清晰起见这就是最终产品的样子。。
https://stackoverflow.com/questions/26826455
复制相似问题